A 8.5-liter sample of a gas has 1.2 mole of the gas. If 0.65 mole of the gas is added, what is the final volume of the gas? Temp
2 answers:
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Answer:
The advantages described below
Explanation:
Advantages of a balanced chemical equation versus word equation:
- easier to read: chemical equations typically only take one line and they include all the relevant information needed. They are short-hand notations for what we describe in words.
- balanced chemical equations show molar ratio in which reactants react and the molar ratio of the products. Those are coefficients in front of the species. This is typically not included in a word equation, for example, hydrochloric acid reacts with potassium hydroxide. The latter statement doesn't describe the molar ratio and stoichiometry.
- includes relevant information, such as catalysts, temperature and pressure above the arrow in the equation. We wouldn't have this in a word equation most of the time.
- shows the stoichiometry of each compound itself, e. g. if we state 'ammonia', we don't know what atoms it consists of as opposed to
.
- includes states of matter: aqueous, liquid, gas, solid. This would often be included in a word equation, however.
Answer : The concentration of and
at equilibrium is, 0.0158 M and 0.00302 M respectively.
Explanation :
First we have to calculate the concentration of
Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:
Initial conc. 0.0163 0.00415 0.00276
At eqm. (0.0163-2x) (0.00415+x) (0.00276+x)
As we are given:
Concentration of at equilibrium = 0.00467 M
That means,
(0.00415+x) = 0.00467
x = 0.00026 M
Concentration of at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M
Concentration of at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M