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3 years ago

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One isotope of carbon has 6 protons and 6 neutrons. The number of protons and neutrons of a second isotope of carbon would be __

___.
a. 7 and 6
b. 7 and 7
c. 6 and 6
d. 6 and 7

2 answers:

bogdanovich [222]3 years ago

7 0

Answer d

Explanation

dexar [7]3 years ago

6 0

D. 6 protons and 7 neutrons

As proton remains constant

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What is the name of the compound CO?

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Carbon monoxide (CO) is the name

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Student A performed gravimetric analysis for sulfate in her unknown using the same procedures we did . Results of her three tria

soldi70 [24.7K]

Answer:

The answer is Sodium Sulfate = Na2SO4

Explanation:

Molar mass of sulfate = 1 (S) + 4 (O) = 1 (32) + 4 (16) = 32 + 64 = 96

Molar mass of sodium sulfate = 2 (23) + 96 = 46 + 96 = 142

% of Sulfate = (96/142)*100 = 67.6%

Percent mistake in Studen A,

(I) % mistake = (67.6 - 68.6)/67.6 = 1.48

(ii) % mistake = (67.6 - 66.2)/67.6 = 2.07

(iii) % mistake = (67.6 - 67.1)/67.6 = 0.74

For understudy B

(I) % mistake = (67.6 - 66.7)/67.6 = 1.33

(ii) % mistake = (67.6 - 66.6)/67.6 = 1.48

(iii) % mistake = (67.6 - 66.5)/67.6 = 1.63

Sutdent An is some how exact.

Understudy B is exact however not precise.

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3 years ago

In a common laboratory experiment in general chemistry students are asked to determine:_____.

Alex787 [66]

<h3>The <u>complete question</u> would be:</h3>

In a common laboratory experiment in general chemistry, students are asked to determine the relative amounts of benzoic acid and charcoal in a solid mixture. Benzoic acid is relatively soluble in hot water, but charcoal is not. Devise a method for separating the two components in the mixture.

<h3>The <u>solution</u> for that would be:</h3>

First you put the mixture in hot water and allow the benzoic acid to separate. Next funnel it and then see what's on the funnel paper. Lastly, heat the leftover water and see what's left after it evaporates.

<h3><u>What are laboratory experiments ?</u></h3>

Using controlled surroundings to test theories, researchers may develop laboratory experiments.
Laboratories are rooms or specially constructed facilities within buildings that are often found on college and university campuses and are utilized for academic research.
It's crucial to differentiate between experiments and other kinds of research investigations carried out in lab settings.
Even if a research study takes place in a lab, it is not always an experiment.
In order to evaluate causal conclusions regarding the links between independent and dependent variables, laboratory studies, like all genuine experimental designs, use procedures of random assignment of participants and control groups.

To view more about experiments, refer to:

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11 months ago

Calculate the molality, molarity, and mole fraction of FeCl3 in a 29.5 mass % aqueous solution (d = 1.283 g/mL).

faltersainse [42]

Answer:

molality FeCl3= 2.579 molal

molarity FeCl3 = 2.333 M

mol fraction FeCl3 = 0.0444

Explanation:

Step 1: Data given

Mass % = 29.5 %

Density = 1.283 g/mL

Molar mass FeCl3 = 162.2 g/mol

Step 2: Calculate mass solution

Suppose we have 1L = 1000 mL solution

Mass solution = 1.283 g/mL * 1000 mL = 1283 grams

Step 3: Calculate mass FeCl3

Mass FeCl3 = 0.295 * 1283 grams

Mass FeCl3 = 378.485 grams

Step 4: Calculate mass of water

Mass water = 1283 - 378.485 = 904.515 grams

Step 5: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 378.485 grams / 162.2 g/mol

Moles FeCl3 = 2.333 moles

Step 6: Calculate moles H2O

Moles H2O = 904.515 grams / 18.02 g/mol

Moles H2O = 50.195 moles

Step 7: Mol fraction FeCl3

Mol fraction FeCl3 = 2.333 / (50.195+2.333)

Mol fraction FeCl3 = 0.0444

Step 8: Calculate molality

Molality = moles FeCl3 / mass H2O

Molality = 2.333 moles / 0.904515 kg

Molality = 2.579 molal

Step 9: Calculate molarity

Molarity = moles / volume

Molarity FeCl3 = 2.333 moles / 1 L

Molarity FeCl3 = 2.333 M

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3 years ago

In some reactions, Be behaves like a typical alkaline earth metal; in others, it does not. Complete and balance the following: (

mina [271]

The correct answer is BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-.

Evaluating be behavior to see :

how it differs from the other Group 2A (2) members.

In this reaction Be behaves like other alkaline earth metals

The complete equation can be given as

BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-

BeCl_2 tends to form a chloro bridged dimer in the vapour state, however at high temperatures of the order of 1200K, this dimer dissociates into the linear monomer.

BeCl_2 has a chain structure in its solid form. Each Be atom in this structure is surrounded by chlorine atoms, two of which are connected by conversion bonds and the remaining two by covalent coordinate connections. This chain structure is displayed.

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1 year ago