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N76 [4]
3 years ago
12

What is the same person's mass on mars, where the acceleration due to gravity is 3.7 m/s2?

Physics
1 answer:
Lilit [14]3 years ago
6 0
We can answer this even though you haven't told us anything from the previous problem that this one refers to. The person's mass stays the same as it was in the earlier problem, because mass is constant no matter where you take it.
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A rocket-driven sled Sonic Wind No. 2, is used for investigating the physiological effects of large accelerations on people. It
rewona [7]

Answer:

The best single equation in order to fin the acceleration is

a=v_f/t=250/2=125m/s^2

Explanation:

The best single equation in order to find the acceleration is the following kinematics equation:

v_f=v_o+at

As the rocket start from the rest, the initial velocity value is zero. Then the acceleration value is:

a=v_f/t=250/2=125m/s^2

7 0
3 years ago
Help Me please!!!!!!!!!!!!!!!!!!!!! This My question on this test! I need This one! PLEASE!!!!!!!!
faltersainse [42]

Answer:

That is gold

Explanation:

3 0
3 years ago
Read 2 more answers
Three moles of an ideal gas undergo a reversible isothermal compression at 22.0°C. During this compression, 1700 J of work is do
densk [106]

Answer:

change in entropy is - 5.7627 J/K

Explanation:

Given data

temperature = 22.0°C = 22 + 273 = 295 K

work is done = 1700 J

to find out

change in entropy

solution

we know that change in entropy = Q /T  ......1

from 1st law of thermodynamic we know

Q =W for change in internal energy = 0

Q = -1700 J

so from equation 1

change in entropy = - 1700 / 295

change in entropy = - 5.7627

so change in entropy is - 5.7627 J/K

5 0
3 years ago
Is orange juice in an orange potential energy or kinetic energy?
kicyunya [14]
It would be potential energy because it is not moving. <span />
3 0
4 years ago
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Find the frequency of a tuning fork that takes2.50×10−3s to complete one oscillation.
maksim [4K]

The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.

Frequency = 1/time period of the oscillation

Frequency of the tuning fork = 1/time period

                                                   =1/2.50×10⁻³

                                                   =400 Hz

Thus the frequency of a tuning fork comes out to be 400 Hz.

Learn more about frequency here, refer to the link;

brainly.com/question/14316711

#SPJ1

6 0
2 years ago
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