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3 years ago

The mass of 29000 N elevator is

Physics

1 answer:

Lana71 [14]3 years ago

5 0

<span>In this case we are given a force of 29,000 N. We know that the equation we can use is:</span>

Force = mass * acceleration

However this is not just any type of force, because this is the weight of the elevator. So when the force is equal to weight, the acceleration acting is simply gravity. Therefore:

weight = mass * gravity

Calculating for mass:

mass = 29,000 N / (9.8 m/s^2)

You might be interested in

A biker can ride at 12 m/s on a level road when there is no wind and at 7.5 m/s on a level road when there is a head wind of 5 m

alexandr402 [8]

Answer:

The answer is " $1.94 \ m^2$ ".

Explanation:

Formula:

$F= \frac{1}{2} \times C_D \times density \times area \times velocity^2\\\\Power (P) = F \times velocity \\\\P = \frac{C_D}{2} \times density \times area \times velocity^3\\$

Given value:

$\ P = 10.25 \ W \\\\\ density = 1.2 \ kg/m^3 \\\\\ velocity= 2.5 \\\\$

$10.25 = \frac{C_D A}{2} \times 1.2 \times 2.5^3\\\\C_D A= \frac{10.25 \times 2 }{1.2 \times 2.5^3}\\\\C_D A = 1.94 m^2\\$

8 0

3 years ago

Mark and Paul are in a race. Mark is 20 meters from the finish line and running at a constant 3.5 m/s. Paul is 5 meters behind h

USPshnik [31]

Answer:

$25 m= 2.7 m/s * (5.71 s)+ \frac{1}{2} a (5.71s)^2$

And solving for a we got:

$9.583 m = \frac{1}{2} a (5.71s)^2$

$a = 0.588 \frac{m}{s^2}$

Explanation:

For this case we have an illustration for the problem on the figure attached.

And we can solve this problem analyzing each one of the runner. Let's begin with Mark

Mark

For this case we know that $V_M = 3.5 m/s$ and th velocity is constant. The distance from Mark and the finish line is $D_M = 20 m$

Since the velocity is constant we can create the following relation:

$D_M = V_M t_M$

And solving for $t_M$ we got:

$t_m = \frac{D_M}{V_M}= \frac{20m}{3.5 m/s}= 5.71 s$

So then Mark will nd the race after 5.71 seconds

Paul

We know that the initial velocity for Paul is given $V_{iP}= 2.7 m/s$ we also know that the total distance between Paul and the finish line is 25 m and we want to find the acceleration that Paul needs to apply in order to tie the race, and Paul have 5.71 sconds in order to reach the finish line.

We can use this formula in order to find the acceleration (because we assume that the acceleration is constant) that he needs to apply:

$x_f = x_i + v_i t + \frac{1}{2} a t^2$

And since $\Delta x = x_f - x_i$ we have this:

$\Delta x= v_i t + \frac{1}{2} a t^2$

And if we replace we have this:

$25 m= 2.7 m/s * (5.71 s)+ \frac{1}{2} a (5.71s)^2$

And solving for a we got:

$9.583 m = \frac{1}{2} a (5.71s)^2$

$a = 0.588 \frac{m}{s^2}$

And the final velocity for Paul using this acceleration would be:

$V_{fP}= V_{iP}+ a_P t = 2.7m/s + 0.588 m/s^2 (5.71s)= 6.057 m/s$

3 0

4 years ago

How does the distance traveled by the coin compare to its displacement after ten flips?

Nataliya [291]

Answer:

The positive velocity occurs the instant the coin leaves our hand. It immediately begins slowing up until its upward velocity becomes zero at the maximum height.

Explanation:

hope helps ohjieun and jannatparia

3 0

3 years ago

Estimate the change in gravitational potential energy when a person with mass 80 kg rise from bed to a standing position. Assumi

Doss [256]

Answer:

change in gravitational potential energy Δ PE = 392 J

Explanation:

given data

mass of the person m = 80 kg

height of the centre of mass Δh = 0.50 m

to find out

change in gravitational potential energy

solution

we get here change in gravitational potential energy that is express here as

change in gravitational potential energy Δ PE = m × g × Δh .........1

put here value we get

change in gravitational potential energy Δ PE = m × g × Δh

change in gravitational potential energy Δ PE = 80 × 9.8 × 0.50

change in gravitational potential energy Δ PE = 392 J

7 0

3 years ago

The neurons of giant squids, for example, consist of axons with very large radii, which allows the squid to react very quickly w

Alinara [238K]

Answer:

100

Explanation:

$\rho_m$ = Resistivity of axon

r = Radius of axon

t = Thickness of the membrane

$\rho_a$ = Resistivity of the axoplasm

Speed of pulse is given by

$v=\sqrt{\dfrac{\rho_mrt}{2\rho_a}}$

So, radius is given by

$r=\dfrac{2\rho_a}{\rho_mt}v^2$

If radius is increased by a factor of 10 new radius will be

$r_2=\dfrac{2\rho_a}{\rho_mt}(10v)^2\\\Rightarrow r_2=100\dfrac{2\rho_a}{\rho_mt}v^2\\\Rightarrow r_2=100r$

So, The radius will increase by a factor of 100.

5 0

4 years ago