The mass of 29000 N elevator is
1 answer:
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#1
for the block of mass 5 kg normal force is given as
friction force is given as
Net force is given as
now we know that
#2
Normal force is given as
now we know that
as object moves with constant velocity
now for coefficient of friction we can use
#3
net force upwards is given as
mass is given as
now as per newton's law we can say
#4
As we know that when block is sliding on rough surface
part a)
net force = applied force - frictional force
part b)
for coefficient of friction we can use
here normal force is given as
now we have
#5
if an object is initially at rest and moves 20 m in 5 s
so we can use kinematics to find out the acceleration
now net force is given as
#6
an object travelling with speed 25 m/s comes to stop in 1.5 s
so here acceleration of object is given as
now the force is gievn as
Answer:
τ=0.060 N.m
Explanation:
By kinematics:
Solving for α:
where ωo = 600*2*π/60; ωf = 0; t=10s
The sum of torque is: