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kow [346]
2 years ago
14

The coils in a motor have a resistance of 0.14 Ω and are driven by an EMF of 62 V.

Physics
1 answer:
Brilliant_brown [7]2 years ago
7 0

The difference in the power required by the motor at start up and at operating speed is 9778.57

<h3>What is power? </h3>

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = voltage (V) × current (I)

P = IV

Power = square voltage (V²) / resistance ®

P = V² / R

<h3>How to determine the power by the EMF</h3>
  • Voltage (V) = 37 V
  • Resistance (R) = 0.14 Ω
  • Power by EMF (P₁) =?

P = V² / R

P₁ = 62² / 0.14

P₁ = 27457.14 watts

<h3>How to determine the power by the back EMF</h3>
  • Voltage (V) = 62 V
  • Resistance (R) = 0.14 Ω
  • Power by back EMF (P₂) =?

P = V² / R

P₂ = 37² / 0.14

P₂ = 9778.57 watts

<h3>How to determine the power difference</h3>
  • Power by EMF (P₁) = 27457.14 watts
  • Power by back EMF (P₂) = 9778.57 watts
  • Difference in power =?

Difference = P₁ - P₂

Difference in power = 27457.14 - 9778.57

Difference in power = 17678.57 watts

Learn more about electrical power:

brainly.com/question/64224

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Explanation:

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42.9 μF

Explanation:

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C = Q/V = 150/3.50 μF = 42.9 μF

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1) Skid

2)<u> </u>Rocking

3) Oversteer situation

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5) Overdriving headlights

6) Hydroplaning

7) Understeer situation

Explanation:

1) A <u>skid</u> results when a vehicle loses part or all of its grip on the road

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What is the acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg
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Answer:

The acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².

Explanation:

Given

  • Force F = 4000 N
  • Mass m = 1240 kg

To determine

Acceleration a = ?

Important Tip:

  • The acceleration of a boat can be found using the formula F = ma

Using the formula

F =  ma

where

  • F is the force (N)
  • m is the mass (kg)
  • a is the acceleration (m/s²)

now substituting F = 4000, m = 1240 in the formula

F =  ma

4000\:=\:1240\:\times a

Switch sides

1240a=4000

Divide both sides by 1240

\frac{1240a}{1240}=\frac{4000}{1240}

Simplify

a=\frac{100}{31}

a=3.2 m/s²

Therefore, the acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².

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