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Aleks [24]
3 years ago
5

What kind of structure do carbon atoms form in an aromatic compound?

Chemistry
1 answer:
Amanda [17]3 years ago
6 0
Carbon atoms form aromatic rings. When there are 3 double bonds and 6 carbons this is called a benzene ring.
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PLEASE HELP WILL BE MARKING BRAINIEST!!!!!
o-na [289]

Answer:water

Explanation:

to easy

6 0
3 years ago
Draw the products of benzoic acid reacting with sodium hydroxide.
Katena32 [7]

Answer:

Products: C6H5COO-Na+ (aq) + H2O (l)

Explanation:

when the benzoic acid react with sodium hydroxide, the acid part i.e carboxyl group is react with the base and produce ionic compound sodium benzoate (C6H5COO-Na+).

Chemical equation:

C6H5COOH + NaOH  → C6H5COO-Na+ + H2O

Chemical reaction with physical states:

C6H5COOH (s) + NaOH (aq) → C6H5COO-Na+ (aq) + H2O (l)

Sodium benzoate is very polar ionic compound and soluble in water. If we add HCl into this solution sodium benzoate will be converted back into benzoic acid.

Properties of benzoic acid:

1. it is colorless solid.

2. it is crystalline in nature.

3. it is aromatic compound with the formula C7H6O2.

4. it is soluble into benzene, alcohol and ether.

5. its molar mass is 122.12 g/mol.

Properties of sodium benzoate:

1. Sodium benzoate is white odorless chemical compound.

2. It is aromatic compound and molecular formula is C7H5NaO2.

3. Its molecular weight is 144.11 g/mol.

4. it is sweet in taste and soluble in water.

5. it is used as preservative because of its antimicrobial properties.

Properties of Sodium hydroxide:

1. it is colorless solid and inorganic compound.

2. it is crystalline in nature.

3. its molar mass is 40 g/mol.

4. its molecular formula is NaOH.

5. its melting point is 318 °C.

6 0
3 years ago
Solution that contains high percentage of the base in solution are called?
g100num [7]

Answer:

Basic solution.

Explanation:

Solution that contains high percentage of the base in solution are called basic solution because it has more amount of 'Hydroxl or Hydroxide' ions or (OH-) ions. When we put few drops of the red litmus solution or paper in the solution which contains high percentage of the base, it turns red colour in to blue.

So, here the blue colour indicates that the solution is basic in nature.

3 0
4 years ago
Read 2 more answers
19) What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?
zloy xaker [14]

Answer: 3M

Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute KOH = 0.6 moles

V_s = volume of solution in ml= 200 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.6moles\times 1000}{200ml}=3mole/L

Therefore, the molarity of solution will be 3M.

8 0
3 years ago
Read 2 more answers
The half-life of bismuth-210, 210bi, is 5 days. (a) if a sample has a mass of 184 mg, find the amount remaining after 15 days.
ASHA 777 [7]

Answer:- 23.0 mg

Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:

lnN=-kt+lnN_0

where, N_0 is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.

From given information, Original amount, N_0 of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days

Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:

k=\frac{0.693}{t_1_/_2}

where, t_1_/_2 is the symbol for half life. let's plug in the value of half like to calculate k:

k=\frac{0.693}{5days}

k=0.1386day^-^1

Let's plug in the values in the first order kinetics equation and solve it for N:

lnN=-0.1386day^-^1(15days)+ln184mg

lnN=-2.079+5.215

lnN = 3.136

N=e^3^.^1^3^6

N = 23.0 mg

So, 23.0 mg of Bi-210 would be remaining after 15 days.

3 0
4 years ago
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