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weeeeeb [17]
4 years ago
5

What's the 6th term in a sequence that starts with -7.5 and has a common ratio of 9?

Mathematics
1 answer:
harina [27]4 years ago
6 0
\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=-7.5\\
r=9\\
n=6
\end{cases}\implies a_6=-7.5\cdot 9^{6-1}
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If the angles of a triangle form an arithmetic sequence, the middle angle must be the average of the three angles, hence 180°/3 = 60°. The sum of the other two is then 180° -60° = 120°

The largest angle is 120° - 23° = 97°.


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The common difference is 37°.
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3 years ago
( 97 )^2 evaluate of the following by using identities​
Neko [114]

Answer:

9409

Step-by-step explanation:

Let's rewrite 97 as 100 - 3.

Identity used :

<u><em>(a - b)² = a² - 2ab + b²</em></u>

Now, evaluating the expression :

⇒ (100 - 3)²

⇒ (100)² - 2(100)(3) + (3)²

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⇒ 9400 + 9

⇒ 9409

8 0
2 years ago
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If h(x) = 48, find x
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Step-by-step explanation:

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3 years ago
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The following data summarizes results from 939 pedestrian deaths that were caused by accidents . If one of the pedestrian deaths
olganol [36]

Answer:

Step-by-step explanation:

Hello!

The contingency table is attached.

The total of pedestrians is 909, not 939, there are 30 accidents less in the given data.

I've calculated the asked probabilities using a total of 909.

1. The probability that the pedestrian was intoxicated or the driver was intoxicated.

Two events are mutually exclusive when the occurrence of one prevents the occurrence of the other in one single performance of the experiment. (i.e there is no intersection between the events P(A∩B)=0)

When two events are mutually exclusive, the probability of the union of both elements is equal to the sum of their individual probabilities P(A∪B)= P(A) + P(B).

When the events aren't mutually exclusive, the probability of their union is equal to the summary of their probabilities minus the probability of the intersection between these two events P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

∪ is the union of both events, in colloquial language represents "or"

∩ is the union of both events, or intersection of the events, in colloquial language represents "and"

In this case P(P₁ ∪ D₁) = P(P₁) + P(D₁) - P(P₁ ∩ D₁) = \frac{306}{909} + \frac{132}{909} - \frac{81}{909} = 0.393

P₁ and D₁ are not mutually exclusive

2. The probability of the pedestrian was intoxicated or the driver was not intoxicated.

These two events aren't mutually exclusive.

P(P₁ ∪ D₂)= P(P₁) + P(D₂) - P(P₁ ∩ D₂)= \frac{306}{909} +\frac{777}{909} *-\frac{225}{909}= 0.944

I hope it helps!

3 0
3 years ago
Help please if you can
r-ruslan [8.4K]

Answer:

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Step-by-step explanation:

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