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ElenaW [278]
3 years ago
12

Please help me ASAP!!!

Chemistry
1 answer:
Bogdan [553]3 years ago
3 0
Answer:

Molecules to moles is a one step conversion.

Explanation:

You need to understand the definition of a mole. It's basically 6.022x10^23 molecules, atoms, pencils, people, etc. it's like a dozen but a giant number. Having this in mind: 1mole=6.022x10^23
So it turns into a stoichiometry problem:
9.3x10^24 molecules (1 mole / 6.022 x 10^23 molecules) = your answer in moles.

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Consider the balanced equation below. 4nh3 3o2 right arrow. 2n2 6h2o what is the mole ratio of nh3 to n2? 2:4 4:2 4:4 7:2
KIM [24]

The required mole ratio of  NH₃ to N₂ in the given chemical reaction is 2:4.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.

Given chemical reaction is:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

From the stoichiometry of the reaction it is clear that:

4 moles of NH₃ = produces 2 moles of N₂

Mole ratio NH₃ to N₂ is 2:4.

Hence required mole ratio is 2:4.

To know more about mole ratio, visit the below link:
brainly.com/question/504601

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Filtration

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When is a roman numeral most likely needed in the name of an ionic compound?
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Draw a lewis structure for ketene, c2h2o, which has a carbon–carbon double bond
MrMuchimi

Visual representation of covalent bonding indicating the valence shell electrons in the molecule, lines represents the shared pair of electron and pair of electrons that are not involved in bonding are represented as dots(lone pairs) are known as Lewis structures.

Compound formation takes place in order to complete the octet of each element that is according to octet rule, each atom forms bond with other atom in order to complete their octet that is to get eight electrons in its valence shell and attain stability.

An organic compound of the form R^{'}R^{''}C=C=O is known as ketene.

The given ketene is C_2H_2O.

The number of valence electron of:

C = 4

H = 1

O = 6

The number of valence electrons in C_2H_2O = 2\times 4+2\times 1+1\times 6 =16

2 electrons are involved in each single bond between carbon and hydrogen and 4 electrons are involved in each double bond formed between carbon-carbon and carbon-oxygen. Hence, the total number of electrons involved in bond formation are 12 and rest 2 pair of electrons are present on oxygen as lone pair of electrons.

Therefore, the attached image is the Lewis structure of C_2H_2O .

8 0
3 years ago
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