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just olya [345]
3 years ago
15

If the altitude of an equilateral triangle is 9 what is the perimeter

Mathematics
2 answers:
Nadya [2.5K]3 years ago
5 0
\text{Altitude formula=}  \dfrac{s \sqrt{3} }{2}  \\  \\ 9= \dfrac{s \sqrt{3} }{2}  \\  \\ s \sqrt{3}=18 \\  \\ s= \dfrac{18}{ \sqrt{3} }   \\  \\ s = \dfrac{18 \sqrt{3} }{3}  \\  \\ s =6\sqrt{3}  \\  \\  \\ P = 3s \\  \\ P=3 \times 6 \sqrt{3}  \\  \\ P = 18 \sqrt{3}  \\  \\  \\ P \approx 3 \times 6 \times 1.73 \\  \\ P \approx 31,14
Volgvan3 years ago
3 0
The angles in an equilateral triangle  are 60 degrees.

sin 60 = 9 / h     where h is  hypotenuse ( = side of the triangle)

h = 9 / sin 60 = 10.392

Perimeter = 3 * h = 31.18  to nearest hundredth
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ale4655 [162]

Correct answer is : Area of triangle is 15\sqrt{3} sq.units

Solution:-

We can do it in 2 methods.

Method 1:-

Given that AB=6, BC=10 and m∠B = 120

Then area of triangle = \frac{1}{2}XbaseXheight

Let us assume AB is base and D is an altitude from C onto AB.

Then sin(60)= \frac{CD}{BC}

          CD = BC sin(60)

Hence height = 10*\frac{\sqrt{3}}{2} = 5\sqrt{3}

Hence area of ΔABC = \frac{1}{2} X6X5\sqrt{3} = 15\sqrt{3} sq.units

Method2:-

Area of triangle = \frac{1}{2} acsin(B)

Here a= BC=10, c=AB=6.

Hence area of triangle = \frac{1}{2}X6X10sin(120) = 15\sqrt{3} sq.units


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3 years ago
PLEASE ANSWER!!! You are helping wish some repairs at home. you drop a hammer and it hits the floor at a speed of 12 feet per se
Andru [333]

Answer:

h = 2.25 m

Step-by-step explanation:

<u><em>Given:</em></u>

Speed = v = 12 ft/sec

Acceleration due to gravity = g = 32 ft/sec²

<u><em>Required:</em></u>

Height = h = ?

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For h, the formula will be:

=> h = \frac{v^2}{2g}

=> h = \frac{(12)^2}{2(32)}

=> h = \frac{144}{64}

=> h = 2.25 m

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