Assume that the length of the rectangle is "l" and that the width is "w".
We are given that:
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15
Substitute with w in equation I to get the length as follows:
l = 2w + 1
l = 2(15) + 1
l = 30 + 1 = 31
Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
12x²-9x = 0
3x(4x-3)=0
4x-3=0
4x=3
x=3/4
so either x = 0 or x = 3/4
<span>93 * 10^9 = 9.3 * 10^10
</span>
Answer:
<h2>
1,800 pictures</h2>
Step-by-step explanation:
Find the diagram attached below with its dimension.
The board is rectangular in nature with dimension of 3.6 m by 1.8 m wall.
Area of a rectangle = Length * Breadth
Area of the board = 3.6 m * 1.8 m
since 1m -= 100cm
Area of the board = 360cm * 180cm
Area of the board = 64,800cm²
If the dimension of a picture on the wall is 6cm * 6cm, the area of one picture fir on the wall = 6cm* 6cm = 36cm²
In order to know the amount of 6cm* 6cm pictures that will fit on the wall, we will divide the area of the board by the area of one picture as shown;
Number of 6cm by 6cm pictures that could fit on the wall
= 64, 800cm²/36cm²
= 1,800 pictures
Answer:
a. Green
b. Blue
c. Red
d. Purple
(Just for clarification, m is the slope and b is the y-intercept.)