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otez555 [7]
3 years ago
14

Determine the volume of an object that has a mass of 455.6 g and a density of 19.3 g/cm3. (1cm3 = 1ml) select one:

Chemistry
1 answer:
Dmitry [639]3 years ago
4 0
The answer is B. The density, or more precisely, the volumetric mass density, of a substance is its mass per unit volume.

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What is the purpose of finding oxidation states in the half-reaction method for balancing equations?
vazorg [7]

Answer:

B. To Identify the half reactions for the equation

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3 years ago
What was the velocity over the entire trip? <br><br> A. -2<br> B. -1<br> C. 0<br> D. 1<br> E. 2
zhannawk [14.2K]
You’re right its A -2
5 0
2 years ago
Is the following equation balanced? SO3 + 2H2O H2SO4 no yes
postnew [5]

Answer: No

Explanation: It's not balanced because four oxygen atoms in H2SO4,  whereas there are 5 oxygen atoms in the reactants side. Also, there's more hydrogen atoms on the reactants side.

I hope this helps!

7 0
3 years ago
What type of compound does the formula, CuCl2, represent?<br> a. ionic salt<br> b. covalent molecule
Rainbow [258]
The answer is:  [B]:  "ionic salt" .
___________________________________________________
Note:  There is no "sharing of electrons" among the elements in this compound; so this compound in NOT a "covalent molecule".

However, there is ionic bonding:  Cu²⁺ and  Cl⁻  ;  to form:  "CuCl₂" .
____________________________________________________ 
7 0
3 years ago
A chemist adds 215.0mL of a 6.0x10^−5/mmolL mercury(II) iodide HgI2 solution to a reaction flask. Calculate the micromoles of me
Snezhnost [94]

The micromoles of mercury(II) iodide : 0.013 μ moles

<h3>Further explanation</h3>

Given

215.0mL of a 6.0x10⁻⁵mmol/L HgI₂

Required

micromoles of HgI₂

Solution

Molarity(M) = moles of solute per liters of solution

Can be formulated :

M = n : V

n = moles

V = volume of solution

V = 215 mL = 0.215 L

so moles of solution :

n = M x V

n = 6.10 mmol/L x 0.215 L

n = 1.312 . 10⁻⁵ mmol

mmol = 10³ micromol

so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles

6 0
2 years ago
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