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otez555 [7]
3 years ago
14

Determine the volume of an object that has a mass of 455.6 g and a density of 19.3 g/cm3. (1cm3 = 1ml) select one:

Chemistry
1 answer:
Dmitry [639]3 years ago
4 0
The answer is B. The density, or more precisely, the volumetric mass density, of a substance is its mass per unit volume.

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Based on the information in the graph, which statement best applies to a gas?
Genrish500 [490]
I think the right answer would be its particles have the most astounding normal dynamic vitality. Gas particles have a tendency to have the most astounding active vitality among the conditions of matter. They move in arbitrary movement. Trust this answers the question. Have a decent day.
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3 years ago
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Which particle has no mass and no charge?<br> O alpha<br> O beta<br> gamma<br> O<br> neutron
Olegator [25]

Answer:

Neutrons

Explanation:

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3 years ago
If I have 2.4g of magnesium, how many g of oxygen(O2 ) will I need to react completely with the magnesium? 2Mg +O2 → MgO
Jet001 [13]

Explanation:

just trying....hope that helps

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3 years ago
A cube of an unknown metal measures 0.250 cm on one side. The mass of the cube is 0.134 g. Which of the following is most likely
rosijanka [135]

Answer:

8.58 g/cm3

Explanation:

density = mass / volume

be attention that the question gives u the length of

one side of the cube so u should calculate the volume

of the cube using your information of math .

1st we calculate the volume of the cube :

 V of cube = a 3= axaxa

                 = 0.250 x0.250 x0.250

                 = 0.0156 cm3

 2nd step

density = mass/volume

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5 0
3 years ago
Calcutale Grxn for the following equation at 25°C: <br><br> 4KClO3(s) → 3KClO4(s) KCl(s)
Step2247 [10]

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

5 0
4 years ago
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