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AleksAgata [21]
3 years ago
5

In a chemical reaction, the difference between the potential energy of the products of the potential energy of the reactants is

equal to the
a) activation energy
b) entropy of the system
c) heat of fusion
d) activation energy
Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
7 0
Your question looks a bit incomplete as you have the same contents in options a) and d). According to your list, I can't see the correct answer, but I can give you one.The difference between the potential energy of the products of the potential energy of the reactants is equal to the enthalpy of the reaction.
ki77a [65]3 years ago
7 0

Answer:

Heat of reaction

Explanation:

The answer isn't present in the choices, but its supposed to be heat of reaction according to my knowledge.

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What is the electron configuration for vanadium (V)? The Periodic Table A. 1s22s22p63s23p64s24d3 B. 1s22s22p63s23p63d5 C. 1s22s2
kramer

The electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 (option D).

<h3>What is electronic configuration?</h3>

Electronic configuration is the the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.

Vanadium is the 23rd element on the periodic table and has chemical symbol V with atomic number 23. It is a transition metal, used in the production of special steels.

This suggests that the electronic configuration of Vanadium will be written as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3

Therefore, the electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3.

Learn more about electronic configuration at: brainly.com/question/14283892

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5 0
2 years ago
Graph of the relationship between mass and thermal energy
elixir [45]

<em>Thermal energy</em> is the sum of the kinetic and potential energies of all the particles in an object.

Assume that you have 250 gL of water and 1 kg of water at the same temperature.

Then, each water molecule has the same kinetic energy.

The larger sample contains four times as many molecules, so it contains four times as much thermal energy.

Thus, thermal energy is directly proportional to mass.

In symbols, <em>KE </em>∝ <em>m</em> or <em>KE = km</em>.

The graph of a direct proportion is a <em>straight line passing trough the origin</em>.

It should look something like the graph below.

6 0
4 years ago
The hydrogen ion​ concentration, ​[H+​], in a certain cleaning compound is left bracket Upper H Superscript plus Baseline right
labwork [276]

<u>Answer:</u> The pH of the cleaning compound is 10.44

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen or hydronium ion concentration that are present in a solution.

The equation representing pH of the solution follows:

pH=-\log[H^+]

We are given:

[H^+]=3.6\times 10^{-11}

Putting values in above equation, we get:

pH=-\log(3.6\times 10^{-11})

pH=10.44

Hence, the pH of the cleaning compound is 10.44

8 0
3 years ago
What are the concentrations of A , A, B , B, and C C at equilibrium if, at the beginning of the reaction, their concentrations a
Elenna [48]

The question is incomplete, here is the complete question:

A reaction

A+B\rightleftharpoons C

has a standard free-energy change of -4.88 kJ/mol at 25°C

What are the concentrations of A, B, and C at equilibrium if at the beginning of the reaction their concentrations are 0.30 M, 0.40 M and 0 M respectively?

<u>Answer:</u> The equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

<u>Explanation:</u>

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K_c

where,

\Delta G^o = Standard Gibbs free energy = -4.88 kJ/mol = -4880 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_c = equilibrium constant of the reaction

Putting values in above equation, we get:

-4880J/mol=-(8.3145J/Kmol)\times 298K\times \ln K_c\\\\K_c=7.17

We are given:

Initial concentration of A = 0.30 M

Initial concentration of B = 0.40 M

Initial concentration of C = 0 M

The chemical reaction follows:

                               A+B\rightleftharpoons C

<u>Initial:</u>                 0.30  0.40      0

<u>At eqllm:</u>         0.30-x   0.40-x    x

The expression of equilibrium constant for the above reaction follows:

K_c=\frac{[C]}{[A][B]}

We are given:

K_c=7.17

Putting values in above equation, we get:

7.17=\frac{x}{(0.30-x)\times (0.40-x)}\\\\x=0.183,0.657

Neglecting the value of x = 0.657, because change cannot be greater than the initial concentration

So, equilibrium concentration of A = (0.30-x)=(0.30-0.183)=0.117M

Equilibrium concentration of B = (0.40-x)=(0.40-0.183)=0.217M

Equilibrium concentration of C = x=0.183M

Hence, the equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

5 0
3 years ago
In titrating 0.20 M hydrochloric acid, HCl, with 0.20 M NaOH at 25°C, the solution at the equivalence point is
xxTIMURxx [149]

Answer:

c) 0.10M NaCl

Explanation:

<em>Options are:</em>

<em>a) 0.20M NaCl</em>

<em>b) Very acidic</em>

<em>c) 0.10M NaCl</em>

<em>d) 0.10M HCl + 0.20M NaOH</em>

<em>e) Slightly acidic.</em>

<em />

Based on the reaction:

NaOH + HCl → H₂O + NaCl

You can see than 1 mole of NaOH reacts per mole of HCl producing 1 mole of NaCl

Assuming 1L of 0.20M HCl reacts with 1L of NaOH, moles of both compounds are:

1L * 0.20mol/L = 0.20 moles reacts. That means moles of NaCl produced are 0.20moles in 2L. Molarity of NaCl is:

0.20mol / 2L = 0.10M NaCl

That means, right option is:

<h3>c) 0.10M NaCl</h3>

8 0
3 years ago
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