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Neporo4naja [7]
3 years ago
14

Which element is classified as a noble gas at STP?(1) hydrogen (3) neon(2) oxygen (4) nitrogen

Chemistry
1 answer:
strojnjashka [21]3 years ago
3 0
Neon is the element that is classified as a noble gas at STP.
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B. same group I believe
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The town in the video stressed using locally made goods instead of imported goods. How could using locally made goods lower CO2
ladessa [460]

Answer:

It reduces the need to import goods

Explanation:

When you buy locally, the products you buy don't come from far away, so they don't have to cross the country (or the ocean) by boat, plane or trucks to reach the market/store where you're buying, at least not from a long distance away.

The distance a vehicle travels, the less CO2 emissions it produces.

If the good you're buying is made/produced only an hour away, that's not much pollution produced compared as if the good has to come from a distant place spending days on highways to reach you.

6 0
3 years ago
Given the reaction:
tino4ka555 [31]

4 moles of NaCl is produced from 2 moles of Na₂CrO₄.

<u>Explanation:</u>

Given reaction is

PbCl₂(aq) + Na₂CrO₄(aq)→ PbCrO₄(s) + 2 NaCl (aq)

It is the balanced equation which means that on both sides of the equation, number of atoms of each element are equal.

From the above balanced equation it says that molar ratio of Na₂CrO₄ to NaCl is 1 : 2.

That is 1 mole of Na₂CrO₄ produces 2 moles of NaCl, so the molar ratio is 1:2.

2 moles of Na₂CrO₄  produces 4 moles of NaCl.

So the molar ratio of Na₂CrO₄ to NaCl is 2: 4.

6 0
3 years ago
What is the definition of DNA in meiosis
Eddi Din [679]

In meiosis, DNA replication is followed by two rounds of cell division to produce four daughter cells, each with half the number of chromosomes as the original parent cell. The two meiotic divisions are known as meiosis I and meiosis II.

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What is the mass percentage of oxygen in Ba3(PO4)2? Please help how do I go about figuring this out?
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Molecular Mass of Compound.

\\ \sf\longmapsto Ba_3(PO_4)_2

\\ \sf\longmapsto 3(137u)+2(39u+4(16u))

\\ \sf\longmapsto 411u+2(39u+64u)

\\ \sf\longmapsto 411u+2(103u)

\\ \sf\longmapsto 411u+206u

\\ \sf\longmapsto 617u

  • Molecular mass of O in compound=16(4)=64u

\\ \sf\longmapsto Mass\%\:of\:O

\\ \sf\longmapsto \dfrac{64}{617}\times 100

\\ \sf\longmapsto \dfrac{6400}{617}

\\ \sf\longmapsto 10.3\%

6 0
3 years ago
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