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Margarita [4]
3 years ago
9

Longitudinal waves do not have

Physics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
E. Nonsense longitudinal waves have all of these properties
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A young man and woman are sitting on opposite sides of a park bench (1m). If the young man has a mass of 70kg and the woman has
ZanzabumX [31]

Answer:

130N

Explanation:

F<em>=</em><em>(</em><em>M1+</em><em>M</em><em>2</em><em>)</em><em>V</em>

<em>F=</em><em> </em><em>(</em><em>7</em><em>0</em><em>+</em><em>6</em><em>0</em><em>)</em><em>*</em><em>1</em>

<em>F=</em><em>1</em><em>3</em><em>0</em><em>*</em><em>1</em>

<em>F=</em><em>1</em><em>3</em><em>0</em><em>N</em><em>/</em><em>/</em>

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3 years ago
How do you use the SI conversion tool to perfom metric conversions?
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Is there supposed to an attachent like a pic or somthing?
4 0
3 years ago
If it were possible to move a star towards the earth then its apparent magnitude number would ______ while its absolute magnitud
ArbitrLikvidat [17]

If it were possible to move a star towards the earth then its apparent magnitude number would decrease while its absolute magnitude number would stay the same.

Definition of apparent magnitude:

The luminosity of a celestial body (such as a star) as observed from the earth compare absolute magnitude.

So for example, the apparent magnitude of the Sun is -26.7 and is the brightest celestial object we can see from Earth. However, if the Sun were 10 parsecs away, its apparent magnitude would be +4.7, only about as bright as Ganymede appears to us on Earth.

Definition of absolute magnitude:

Absolute magnitude is a measure of the luminosity of a celestial object on an inverse logarithmic astronomical magnitude scale.

To learn more about apparent magnitude here

brainly.com/question/2949443

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5 0
2 years ago
Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vert
chubhunter [2.5K]

Answer:

362.41 km/h

Explanation:

F = Force

m = Mass = 84 kg

g = Acceleration due to gravity = 9.81 m/s²

C = Drag coefficient = 0.8

ρ = Density of air = 1.21 kg/m³

A = Surface area = 0.04 m²

v = Terminal velocity

F = ma

F=\frac{1}{2}\rho CAv^2\\\Rightarrow mg=\frac{1}{2}\rho CAv^2\\\Rightarrow v=\sqrt{2\frac{mg}{\rho CA}}\\\Rightarrow v=\sqrt{2\frac{20\times 9.81}{1.21\times 0.8\times 0.04}}\\\Rightarrow v=100.66924\ m/s

Converting to km/h

100.66924\times 3.6=362.41\ km/h

The terminal velocity of the stone is 362.41 km/h

5 0
3 years ago
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1) A satellite in orbit around Earth is in uniform circular motion. What is the angle between the velocity vector and accelerati
artcher [175]

Answer:90

Explanation: bc i looked it up

6 0
1 year ago
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