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Hitman42 [59]
3 years ago
10

A body moving at .500c with respect to an observer

Physics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

0.8c and -0.14c

Explanation:

The first fragment will have a speed of +0.5c respect of a frame of reference moving at +0.5c

Lest name v the velocity of the frame of reference, and u' the velocity of the object respect of this moving frame of reference.

The Lorentz transform for velocity is:

u = (u' + v) / (1 + (u' * v) / c^2)

u = (0.5c + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = 0.8c

The other fragment has a velocity of u' = -0.6c respect of the moving frame of reference.

u = (-0.6v + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = -0.14c

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2 years ago
What would happen when two or more capacitors are connected in parallel across a potential difference?
Varvara68 [4.7K]

Answer:

The Current Iₜ = I₁ + I₂ + I₃

Charge Qₜ = Q₁ + Q₂ + Q₃

Potential difference Vₜ = V₁ = V₂ = V₃

The total capacitance Cₜ = C₁ + C₂ + C₃

Explanation:

According to the attached image;

For parallel arrangements of capacitors, the current flowing through each of the capacitors sums up to the total current flowing through the circuit;

Iₜ = I₁ + I₂ + I₃

Also the charge storage by each capacitor sums up to give the total charge stored;

Qₜ = Q₁ + Q₂ + Q₃

The potential difference across each of the capacitors are the same and equal to the total voltage across the circuit;

Vₜ = V₁ = V₂ = V₃

The total capacitance equals the sum of the capacitances of each of the capacitors;

Cₜ = C₁ + C₂ + C₃

6 0
3 years ago
A 40kg rock falls off a cliff that is 50 meters high. How fast is the speed of the rock when it hits the ground
Oksi-84 [34.3K]

31.3m/s

Explanation:

Given parameters:

Mass of rock = 40kg

Height of cliff = 50m

Unknown:

Speed of rock when it hits ground = ?

Solution:

We are going to use the appropriate motion equation to solve this problem

The rock is falling with the aid of gravitational force. The force is causing it to accelerate with an amount of velocity.

  Using;

                      V²  = U² + 2gH

V = unknown velocity

U = initial velocity = O

g = acceleration due to gravity = 9.8m/s²

H = height of fall

since the initial velocity of the bodyg is 0

     V²  = 2gH

    V= √2gH = √2 x 9.8 x 50 = 31.3m/s

learn more:

Velocity brainly.com/question/4460262

#learnwithBrainly

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To measure the height of a building without a ruler or tape measure, an engineer drops a rock off the top of the building and fi
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The relevant equation we can use in this problem is:

h = v0 t + 0.5 g t^2

where h is height, v0 is initial velocity, t is time, g is gravity

 

Since it was stated that the rock was drop, so it was free fall and v0 = 0, therefore:

h = 0 + 0.5 * 9.81 m/s^2 * (4.9 s)^2

<span>h = 117.77 m</span>

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What does it mean by that "length of an object is m"​
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Meters ?? or just a variable
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