A police officer uses a radar gun to determine the speed of a car. A specialized radar gun uses ultraviolet light to determine s
1 answer:
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Answer:
The acceleration of car 2 is four times of the acceleration of car 1.
Explanation:
The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :
In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.
So,
1 and 2 represent car 1 and car 2 respectively.
So,
So, the acceleration of car 2 is four times of the acceleration of car 1.
Answer:
Explanation:
Frequency of signal = 1260 KHz
= 1260 x 10³ = 126 x 10⁴ Hz
velocity of wave = 3 x 10⁸ m /s
wavelength = velocity / frequency
=
= 238 m
b )E(t) = E0 sin(2πft)
E(t) = 0.41 sin(2πft)
when t = 4.8 μs
= 4.8 x 10⁻ ⁶
E(t) = 0.41 sin(2π x 126 x 10⁴ x4.8 x 10⁻ ⁶ )
= 0.41 sin(2π x 126 x 10⁴ x4.8 x 10⁻ ⁶ )
= 0.41 sin(37.98 rad )
= .11 N/C