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seraphim [82]
3 years ago
15

A police officer uses a radar gun to determine the speed of a car. A specialized radar gun uses ultraviolet light to determine s

peed. What describes the waves used
Physics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

Radio Waves

Explanation:

Radio wave is a type of electromagnetic radiation notorious for their use in technologies used for communication like air traffic control, mobile phones, televisions and remote-controlled toys. Radio waves have the longest wavelength in the electromagnetic spectrum and are easily transmitted through air.

A radar gun uses radio waves to tell how far away an object is. To do that, the radar tool emits a focused radio wave and listens for any echo. If there is an item, say a car within the route of the radio wave, it's going to replicate some of the electromagnetic energy, and the radio wave will return to the radar gun. Radio waves flow via the air at a steady pace, so the radar gun can calculate how far the object is based totally on how long it takes the radio signal to return.

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Two vectors A and B are at right angles to each other. The magnitude of A is 3.00. What should be the length of B, so that the m
AfilCa [17]

Answer: length of B =4.00

Explanation:

for  the vectors A and B and the angle between them as  x.

Magnitude of the sum of A and B is  given as = √(A²+B²+2ABcosx

where

Magnitude of A  = 3.00

Magnitude of the sum of A and B is  5.00

5.00=√(A²+B²+2ABcos90°

5.00= √3² +b² +0

5²= 3² +b²

25=9+b²

b²= 25-9

b² = 16

b=  √16

b= 4

7 0
3 years ago
When I double displacement reaction takes place, one of the products must be_______.
sattari [20]

Answer:

the answer would be Salt

Explanation:

3 0
3 years ago
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What are 2 uses for this tiny electromagnet?
Ray Of Light [21]

Electromagnets are used in all kinds of electric devices, including hard disk drives, speakers, motors, and generators, as well as in scrap yards to pick up heavy scrap metal. They're even used in MRI machines, which utilize magnets to take photos of your insides!

6 0
4 years ago
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An alpha particle collides with an oxygen nucleus, initially at rest. The alpha particle is scattered at an angle of 25.0° above
Greeley [361]

Answer:

v_{i}= 19\times 10^5\ m/s

Explanation:

given,

scattering angle of alpha particle = 25.0°  above its initial direction of motion

oxygen nucleus recoils at = 50.0° below this initial direction.

final speed of the oxygen = 2.08×10⁵ m/s

mass of alpha particle = 4.0 u

mass o oxygen nucleus = 16 u

momentum conservation along x- axis

m_{a}v_{i} = m_a v_a cos\theta + m_o v_o cos\theta

4v_{i} = 4\times v_a cos25^0 + 16\times 2.08 \times 10^5 cos50^0

v_{i}= \dfrac{3.625\times v_a+ 21.39\times 10^5}{4}....(1)

Along y-direction

0 = m_av_a sin \theta - m_ov_o sin\theta

0 = 4\times v_a sin 25 - 16\times  2.08 \times 10^5 sin50^0

v_a = \dfrac{25.49 \times 10^5}{1.69}

v_a = 15.082\times 10^5\ m/s

putting value in equation (1)

v_{i}= \dfrac{3.625\times 15.082\times 10^5+ 21.39\times 10^5}{4}

v_{i}= 19\times 10^5\ m/s

5 0
4 years ago
Need help with number 5 ASAP please
topjm [15]

Explanation:

The current flow of electrons for all of the light bulbs would be interrupted. It is similar or 'breaking' a circuit.

5 0
3 years ago
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