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4 years ago

Which of the following could lead to static discharge?

Chemistry

1 answer:

Ahat [919]4 years ago

3 0

Answer:

Static charge is caused by the build up of electrons on the atoms of an object.

Explanation:

You can experience this yourself with a balloon! Rub it against your head in order to disassociate electrons from it, causing it to be charged - you can now put it on a wall and notice how it 'sticks' to it. You can also cause this effect by jumping on a trampoline, causing static charge to be built up - which is sometimes why you feel a little 'zap' when you touch the sides of it.

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Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The

yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of $N_2$ = 8.00 atm

The partial pressure of $O_2$ = 5.00 atm

$K_p$ = 0.0025

The balanced equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initial pressure 8.00 5.00 0

At eqm. (8.00-x) (5.00-x) 2x

The expression of equilibrium constant $K_p$ for the reaction will be:

$K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}$

Now put all the values in this expression, we get :

$0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}$

By solving the terms, we get:

$x=0.15atm$

The equilibrium partial pressure of $N_2$ = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of $N_2$ is 7.8 atm.

3 0

4 years ago

Calculate Delta E when 33.0 g of carbon dioxide sublimes at 77.0 K and 1 ATM

bagirrra123 [75]

To solve this problem, we establish the general energy balance:

ΔE = ΔU + ΔKE + ΔPE
ΔE = Q + W

Q + W = ΔU + ΔKE + ΔPE

In this case, ΔKE and ΔPE are both zero or negligible.

Given:

m = 33.0 grams of CO2
Tsub = 77 K
P = 1 atm

ΔE = Q + W
ΔE = mCpΔT + ΔPV

solve for mCpΔT, find the value of Cp for CO2, then solve for Q. Next, solve for W using the ideal gas law. Add the two values and that will be the value of the delta E.

3 0

4 years ago

When a solution of NaI reacts with a solution of AgNO3, what is the net ionic equation?

Leni [432]

Answer:

Ag⁺(aq) + I⁻(aq) → AgI(s)

Explanation:

Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.

In the reaction:

AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).

The ionic equation is:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).

Now, listing only the species that are participating in the reaction:

3 0

4 years ago

Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.

aliina [53]

Answer:

x= 138.24 g

Explanation:

We use the avogradro's number

6.023 x 10^23 molecules -> 1 mol C2H8

26.02 x 10^23 molecules -> x

x= (26.02 x 10^23 molecules * 1 mol C2H8 )/6.023 x 10^23 molecules

x= 4.32 mol C2H8

1 mol C2H8 -> 32 g

4.32 mol C2H8 -> x

x= (4.32 mol C2H8 * 32 g)/ 1 mol C2H8

x= 138.24 g

4 0

4 years ago

Will give brainliest!!!!

butalik [34]

According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products. The mass of products and reactants will only differ during a nuckear reaction
Changing of the physical state of water is not a nuclear reaction. So becoz of that the mass will remain constant without any change.

3 0

3 years ago

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