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3 years ago

Will give brainliest!!!!

Chemistry

2 answers:

EleoNora [17]3 years ago

8 0

<u>Answer:</u> Yes, the mass will remain conserved during a physical change.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed, but it can only be transformed from one form to another form. In a reaction, total mass on the reactant side will always be equal to the total mass on the product side.

We are given:

Mass of water = 200 g

So, during a physical reaction of water, the mass will remain conserved.

Thus, the answer will be yes, the mass will remain conserved during a physical change.

butalik [34]3 years ago

3 0

According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products. The mass of products and reactants will only differ during a nuckear reaction
Changing of the physical state of water is not a nuclear reaction. So becoz of that the mass will remain constant without any change.

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The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera

marshall27 [118]

Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2 cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius

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2 years ago

Which of the following is an anion?<br> A. O^2- <br> C. Al^3+ <br> D. H

kifflom [539]

The correct answer is A. O^2-

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2 years ago

Which of the following answers below is the correctly balanced half-reaction for the reduction of the SO4 ^-2 ion in acid soluti

Rom4ik [11]

Answer:

Explanation:

The oxidation number of Sulphur in SO4^2- is;

x + 4(-2) = -2

x - 8 = -2

x = -2 + 8

x = 6

Now,

the oxidation number of sulphur in H2SO3 is

2 (1) + x + 3(-2) = 0

2 + x -6 = 0

-4 + x = 0

x = 4

Hence, the oxidation number of sulphur changed from +6 to +4 which signifies gain of two electrons as shown in option C.

8 0

3 years ago

Write a balanced chemical equation, including physical state symbols, for the combustion of gaseous butane into gaseous carbon d

Phantasy [73]

Answer:1.

1.Balanced equation

C4H10 + 9 02 ==> 5H20 +4CO2

2. Volume of CO2 =596L

Explanation:

1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;

CxHy +( x+y/4) O2 ==> y/2 02 + xCO2

Where x and y are number of carbon and hydrogen atoms respectively.

For butane (C4H10)

x=4 and y=10

Therefore

C4H10 + 9 02 ==> 5H20 +4CO2

2. Mass of butane = 0.360kg

Molar mass of C4H10 = ( 12×4 + 1×10)

= 48 +10=58g/mol= 0.058kg/mol

Mole = mass/molar mass

Mole = 0.360/0.058= 6.2moles

From the stoichiometric equation

1mole of C4H10 will gives 4moles of CO2

Therefore

6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2

Using the ideal gas equation

PV=nRT

P= 1.0atm

V=?

n= 24.8mol.

R=0.08206atmL/molK

T=20+273=293

V= 24.8 × 0.08206 × 293

V= 596L

Therefore the volume of CO2 produced is 596L

8 0

2 years ago

0. 102 g of an unknown compound dissolved in 100. Ml of water has an osmotic pressure of 28. 1 mmhg at 20°c. Calculate the molar

Daniel [21]

The molar mass of the compound is 68 g/mol.

<h3>What is the molar mass?</h3>

The Osmotic pressure can be obtained from the relationship;

π= iCRT

π= osmotic pressure = 28.1 mmHg or 0.037 atm

i = Vant Hoff factor = 1

C = concentration = ?

R = gas constant = 0.082 atmLK-1Mol

T = temperature = 20°c + 273 = 293 K

C = π/iRT

C = 0.037/1 * 0.082 * 293

C = 0.0015 M

Now;

Number of moles = C/V = 0.0015/100 * 10^-3

= 0.015 moles

Number of moles = mass/molar mass

Molar mass = mass/Number of moles = 0. 102 g/ 0.015 moles = 68 g/mol

Learn more about molar mass:brainly.com/question/22997914

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2 years ago