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Elanso [62]
3 years ago
6

Will give brainliest!!!!

Chemistry
2 answers:
EleoNora [17]3 years ago
8 0

<u>Answer:</u> Yes, the mass will remain conserved during a physical change.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed, but it can only be transformed from one form to another form. In a reaction, total mass on the reactant side will always be equal to the total mass on the product side.

We are given:

Mass of water = 200 g

So, during a physical reaction of water, the mass will remain conserved.

Thus, the answer will be yes, the mass will remain conserved during a physical change.

butalik [34]3 years ago
3 0
According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products. The mass of products and reactants will only differ during a nuckear reaction
Changing of the physical state of water is not a nuclear reaction. So becoz of that the mass will remain constant without any change.
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What does the second law of thermodynamics say? O A. The entropy of the universe is increasing. B. A system at equilibrium has n
gayaneshka [121]

Answer:

A.  The entropy of the universe is increasing.(always)

Explanation:

The Second Law of Thermodynamics states that Entropy cannot decrease, because it keeps increasing and increasing and increasing. It will always stay on the increasing side.

<u><em>Hope this helps!</em></u>

<u><em>Please Mark Brainliest!</em></u>

7 0
2 years ago
Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v
Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

Db = Mb/Vb (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: Vb = Vg + Vk (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

Db = (Mg + Mk) / (Vg + Vk)

Db = (Dg * Vg + Dk * Vk)/(Vg + Vk) (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

SG = Substance Density / Reference Density

Therefore:

Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)

SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb * (Vg + Vk) = SGg * Vg + SGk * Vk

SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk

Replacing with the Specific Gravity data, we obtain:

0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk

0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk

0.07 * Vg = 0.05 * Vk

Vg/Vk = 0.05/0.07

Vg/Vk = 0.71

8 0
2 years ago
A conservation easement would be best suited to offset which of the following threats to boidiversity?
Leto [7]
Overharvesting that would be your answer!
3 0
2 years ago
Read 2 more answers
Question 1:
Alona [7]

Question 1:

(a) Sulfurous acid: H2SO3

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Nitric acid: H2NO3

Question 2:

To calculate the pH, based on concentration of H+ ions, there is one formula:

ph =   - log_{10}(c(h + ))

So the pH of this solution is

-  log_{10}( {10}^{ - 9} )  = 9

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5 0
3 years ago
How is 0.246¯¯¯¯ written as a fraction in simplest form?
KiRa [710]
0.246 =  \dfrac{246}{1000} = \dfrac{246 \div 2}{1000 \div 2} = \dfrac{123}{500}
4 0
2 years ago
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