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netineya [11]
3 years ago
15

Calculate Delta E when 33.0 g of carbon dioxide sublimes at 77.0 K and 1 ATM

Chemistry
1 answer:
bagirrra123 [75]3 years ago
3 0
To solve this problem, we establish the general energy balance:

ΔE = ΔU + ΔKE + ΔPE 
ΔE = Q + W

Q + W = ΔU + ΔKE + ΔPE

In this case, ΔKE and ΔPE are both zero or negligible.

Given:

m = 33.0 grams of CO2
Tsub = 77 K
P = 1 atm

ΔE = Q + W
ΔE = mCpΔT + ΔPV

solve for mCpΔT, find the value of Cp for CO2, then solve for Q. Next, solve for W using the ideal gas law. Add the two values and that will be the value of the delta E. 
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Which instrument is used to observe space system from Earth?
Vlad [161]

Answer:

The telescope is used.

3 0
3 years ago
Read 2 more answers
It takes 167 s for an unknown gas to effuse through a porous wall and 99 s for the same volume of n2 gas to effuse at the same t
irakobra [83]

Answer : The molar mass of the unknown gas will be 79.7 g/mol


Explanation : To solve this question we can use graham's law;


Now we can use nitrogen as the gas number 2, which travels faster than gas 1;

So, 167 / 99 = 1.687 So the nitrogen gas is 1.687 times faster that the unknown gas 1

We can compare the rates of both the gases;


So here, Rate of gas 2 / Rate of gas 1 = \sqrt{(molar mass 1 / molar mass 2)}

Now, 1.687 = square root [\sqrt{(molar mass 1) / (28.01 g/mol N_{2})} ]


When we square both the sides we get;


2.845 = (molar mass 1) / (28.01 g/mol N2)


On rearranging, we get,


2.845 X (28.01 g/mol N2) = Molar mass 1

So the molar mass of unknown gas will be = 79.7 g/mol

3 0
3 years ago
If an object has more positive charges than negative charges, the object has an overall?
djyliett [7]
The object has an overall positive charge.
7 0
3 years ago
A) The equilibrium shifts to the left, producing more H3O+.
Lunna [17]

Answer: these are just options, what is the main question, without it, we cannot determine which option is correct, so please repost the question.

5 0
3 years ago
Convert 1.45 × 1024 atoms of carbon to moles of carbon.
anygoal [31]
1 mol = 6.02 * 10^23 atoms of carbon
x mol = 1.45 * 10^24 atoms of carbon

1/x =6.02*10^23 / 1.45 * 10^24

6.02 * 10^23 x = 1.45 * 10^24
x = 1.45 * 10^24 / 6.02 * 10^23
x = 2.41 mols of carbon
8 0
3 years ago
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