From the calculation, the molar mass of the solution is 141 g/mol.
<h3>What is the molar mass?</h3>
We know that;
ΔT = K m i
K = the freezing constant
m = molality of the solution
i = the Van't Hoft factor
The molality of the solution is obtained from;
m = ΔT/K i
m = 3.89/5.12 * 1
m = 0.76 m
Now;
0.76 = 26.7 /MM/0.250
0.76 = 26.7 /0.250MM
0.76 * 0.250MM = 26.7
MM= 26.7/0.76 * 0.250
MM = 141 g/mol
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Answer:
Explanation:
The formula of the reaction:
KClO₂ → KCl + O₂
To assign oxidation numbers, we have to obey some rules:
- Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
- The charge on simple ions signifies their oxidation number.
- The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.
The oxidation number of K in KClO₂:
K + (-1) + 2(-2) = 0
K-5 = 0
K = +5
The oxidation number of K in KCl:
K + (-1) = 0
K = +1
The oxidation number Cl in KClO₂ is -1
For Cl in KCl, the oxidation number is -1
For O in KClO₂, the oxidation number is (2 x -2) = -4
For O in O₂, the oxidation number is 0
K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.
O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.
The subatomic particle that gives off visible light is electrons
14.7lb/in²
Explanation:
This is a conversion problem from atm to pounds per square inch
Pressure is the combined force per unit area of substance on another.
Given pressure = 0.5atm
To solve this problem ;
Convert from atm to N/m² to pound per square inch
1 atm = 101325N/m²
0.5atm = 0.5 x 101325 = 50,662.5N/m²
now we need to convert to pound per square inch;
1N = 0.225lb
1m = 39.37in
Solving;
101325 N
= 14.7lb/in²
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Answer:
See below
Explanation:
<u>Specific Heat of water</u> = 4.186 J/(g-C)
J/(g-C) multiplied by g and C results in J
4.186 * 540 * (95-32) = <u>142 407 .72 J</u>