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3 years ago

Balance the following reaction. 2Ca3(PO4)2 + C + 6SiO2 → CaSiO3 + P4 + CO

Chemistry

2 answers:

MakcuM [25]3 years ago

7 0

Answer:

First one is (10) , second one is (6) , and third one is (10).

Explanation: 10 , 6 , 10 is the correct order!

miskamm [114]3 years ago

3 0

Answer:

2Ca₃(PO₄)₂ + 10C + 6SiO₂ → 6CaSiO₃ + P₄ + 10CO.

Explanation:

To balance a chemical reaction, we should apply the law of conservation of mass.

Law of conversation of mass states that the no. of atoms is equal in both sides of the chemical reaction.

So, the balanced chemical reaction is:

<em>2Ca₃(PO₄)₂ + 10C + 6SiO₂ → 6CaSiO₃ + P₄ + 10CO.</em>

that 2 mol of Ca₃(PO₄)₂ react with 10 mol of C and 6 mol of SiO₂ to produce 6 mol of CaSiO₃, 1 mol of P₄ and 10 mol of CO.

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Determine the volume of fluid in the graduated cylinder 12.8ml 12.7ml 12.78ml 12.88

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Answer:

the volume is 12.79ml

Explanation:

12.8+12.7+12.78+12.88=51.16

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3 years ago

What is the rule for determining the mass of an atom

Elena-2011 [213]

Answer:

For any given isotope, the sum of the numbers of protons and neutrons in the nucleus is called the mass number. This is because each proton and each neutron weigh one atomic mass unit. By adding together the number of protons and neutrons and multiplying by 1, you can calculate the mass of the atom.

5 0

3 years ago

If body fats has a density of 0.94 g/mL and 3.0 liters of fat are removed, how many pounds of fat were removed from the patient?

-Dominant- [34]

Answer:

6.217 pounds

Explanation:

We are given;

Density of body fats 0.94 g/mL
Volume of fats removed = 3.0 L

We are required to determine the mass of fats removed in pounds.

We need to know that;

Density = Mass ÷ volume

1 L = 1000 mL, thus, volume is 3000 mL

Rearranging the formula;

Mass = Density × Volume

= 0.94 g/mL × 3000 mL

= 2,820 g

but, 1 pound = 453.592 g

Therefore;

Mass = 2,820 g ÷ 453.592 g per pound

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4 0

4 years ago

A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil

Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V $_1$ ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V $_1$ ) = 1.50 L,

Initial moles ( n $_1$ ) = 3.00 mol,

Final Volume ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V $_2$ ).

P $_1$ V $_1$ / n $_1$ T $_1$ = P $_2$ V $_2$ / n $_2$ T $_2$ - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V $_1$ / n $_1$ = V $_2$ / n $_2$ - isolate V $_2$ ,

V $_2$ = V $_1$ n $_2$ / n $_1$ = 1.50 L $*$ 2.5 mol / 3.00 mol = ( 1.5 $*$ 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0

4 years ago