Answer:
No, it is not necessary for them to have same mass.
Explanation:
Let both bodies have a density d1 and d2 respectively.
Since their volumes are equal V1 = V2
we know that, https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D
Hence, d1 = and d2 =
Taking the ratio of densities,we get
This implies that unless the bodies have same densities, the mass of the two bodies will not be same.
<span>won
adjective
Verb phrases are verbs that may function as a predicate, adjective, or adverb. </span>
(a) "That he said" is an adjective modifying "word". However, this contains the s ubject"he" and the verb "said". It is a clause and NOT a phrase. Phrases can only have either a verb or a noun.
<span>(b) There's only one verb "was" but it does not come with a complement, object, modifier, or other verb. Hence, it's NOT a verb phrase. </span>
<span>(c) "Shall be" consists of the modal shall and the be-verb be. This is a perfect example of a verb phrase that functions as a VERB PHRASE. </span>
<span>(d) "Roared" and "charged" are two verbs referring to different subjects. They do not come with a complement, object, modifier, or another verb. Hence, they're NOT a verb phrase. "As the bull charged" is a clause and not a phrase.</span>
Answer:
Angle is 55.52°
and Initial Speed is v=26.48 m/s
Explanation:
Given data

Applying the kinematics equations for motion with uniform acceleration in x and y direction
So

Put the value of v₀ from equation (1) to equation (2)
So

Put that angle in equation (1) or equation (2) to find the initial velocity
So from equation (1)

Deposition is the geological process in which sediments, soil and rocks are added to a landform or landmass
The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.
So since the boat has a lower density than the water, it will float.
So the answer is choice B