How can you double the frequency of a wave if you have control over both the wavelength and the wave velocity?
2 answers:
Answer:
Either double the speed or reduce the wavelength to half
Explanation:
We know that velocity of the wave is given by velocity=wavelength ×frequency
So
As in the question it is given that we have control on both velocity and wavelength
So we have to double the the frequency then we can double the speed or reduce the wavelength to half
Answer:
Change the wavelength to half while keeping velocity constant or change the wave velocity to 2 times while keeping wavelength constant.
Explanation:
The frequency of a wave can be defined as the rate of change of wave speed with respect to the wavelength of the wave.
Mathematically,
Here, v is the velocity, lambda is the wavelength, and f is the frequency of the wave.
If the observer want to double the frequency of the wave, then he should increase the wave velocity two times and take wavelength constant for this case or either he should half the wavelength of the wave to take the velocity of the wave constant.
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Considering the Coulomb's Law, the magnitude of the Coulomb force is 3.1865 N.
<h3>Coulomb's Law</h3>Charged bodies experience a force of attraction or repulsion on approach.
From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.
From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
where:
- F is the electrical force of attraction or repulsion. It is measured in Newtons (N).
- Q and q are the values of the two point charges. They are measured in Coulombs (C).
- d is the value of the distance that separates them. It is measured in meters (m).
- K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹
.
The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
<h3>This case</h3>In this case, you know that:
- The two uncharged sphere are separated by the distance of d= 3.50 m
- The number of electrons are 1.30×10¹².
- Electrons is elementary charge and charges on both the sphere is same. The value of electron is 1.602×10⁻¹⁹ C. This is, Q=q=1.30×10¹²×1.602×10⁻¹⁹ C= 2.0826×10⁻⁷ C
Replacing in Coulomb's Law:
Solving:
<u><em>F= 3.1865 N</em></u>
Finally, the magnitude of the Coulomb force is 3.1865 N.
Learn more about Coulomb's Law:
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