Answer:
Speed of cart's might be less than the high speed after 5 seconds.
Explanation:
Given that,
A fan cart with the fan set to high rolled across the floor.
Let the speed of fan cart with set to high is
per second.
The fan supplies a force to the cart. If a lower fan speed were used, less force would be applied. This would cause a slower change in the cart's speed. So, the cart would be rolling more slowly than
per second after 5 seconds. The speed of cart's might be less than
per second.
Force is needed
A. for a moving object to keep moving at the same speed and direction
B. for a moving object to change its speed
C. for a motionless object to remain still
D. to prevent a moving object from turning
Hence,
Speed of cart's might be less than the high speed after 5 seconds.
Answer:
Explanation:
Given:
- Mass of 1st body =

- Mass of 2nd body =

To Find:
- Magnitude of gravitational force
Solution:
Here, we have a formula
<u>Substituting the values</u>




Know More:
The applied formula for the above solution is

where,
- F
= Gravitational force - G = Gravitational constant
- M
= mass of 1st body - M
= mass of 2nd body - r = distance between two bodies
10cm per beat, it would take 3 beats to travel 30cm x
Answer:
The magnitude of the rate of change of the child's momentum is 794.11 N.
Explanation:
Given that,
Mass of child = 27 kg
Speed of child in horizontal = 10 m/s
Length = 3.40 m
There is a rate of change of the perpendicular component of momentum.
Centripetal force acts always towards the center.
We need to calculate the magnitude of the rate of change of the child's momentum
Using formula of momentum


Put the value into the formula


Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.
Answer:
Explanation:
The speed of sound in air to be 343 m/s.
Given:
distance 'd' = 5 m
L = 12 m
It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference'y' at 1 m distance from the equidistant position
Since
λ/2 = yd/L
λ/2 = (1 x 5)/12
λ = 0.833m
Frequency of the sound is given by,
f = v / λ => 343 / 0.833
f=411.6 Hz