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Travka [436]
3 years ago
8

Three balloons are inflated to the same size. The three balloons are submerged in buckets filled with ice water, tap water and w

ater heated to 65°C. What results would you expect from this experiment? A) All the balloons would shrink. B) All the balloons would expand. C) The balloon in the ice water would expand. D) The balloon in the 65°C water would expand.
Physics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

D

Explanation:

it is D

Juliette [100K]3 years ago
3 0
The correct answer would be (D)
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Edward runs with a speed of 3m/s. How long would it take him to run 2km? Give your answer in seconds to four significant figures
Whitepunk [10]

Answer:

666.6 seconds

Explanation:

if he runs at 3m/sec he will achieve the goal of 2000m in 666.6 seconds. just divide - 3/2000.

note we have changed 2km to 2000metres

5 0
3 years ago
U guys are the best I’m surprised I’m getting all of this right
ella [17]
The answer is B, 1/4 of the cake
5 0
3 years ago
Read 2 more answers
A florescent light tube usually contains what?
Nady [450]

Answer:

mercury vapour

Explanation:

it contains many other gases and it contains mercury vapour

4 0
4 years ago
How does the approximate number of atoms
Dima020 [189]
Consider the Earth as a sphere. Think of the atmosphere as having a height of say about 20000 m. The volume of a sphere is 4/3 * pi * r ^3.
Find the volume of a sphere of radius 6020000 m and subtract the volume of the Earth which is a sphere of radius 6000000 m (approx).
This would be the volume of air in m^3.

Approximate the lungs as a cube, it would be approx 0.2m x 0.2m x 0.2 m = 0.008 m^3

Divide the volume of air around the Earth by 0.008.

0.001 m^3 of air contains about 6 x 10^23 molecules which is about 12 x 10^23 atoms.

If your lungs are 0.008 m^3 then that would be about 96 x 10 ^23 or about 10^25 atoms.

Compare that number with the earlier number when dividing air in the atmosphere by 0.008.

I hope this helps. :)
7 0
4 years ago
An insulated beaker with negligible mass contains liquid water with a mass of 0.240 kg and a temperature of 75.8°C . How much ic
sweet [91]

Answer:

Explanation:

Let mass of ice required is m kg

Heat gained by ice to attain zero degree

= m x 14.1 x 2100

= 29610m J

Heat gained by ice to melt = m x 3.34 x 10⁵ J

= 334000m J

Heat gained by water at zero degree to warm up to 27 degree

m x 4190 x 27 =113130 J

Total heat gained = 476740m J

Heat lost by hot water to cool up to 27 degree

.24 x 4190 x ( 75.8 - 27 )

= 49073.28 J

Heat lost = heat gained

476740 m = 49073.28

m = 49073.28/476740 kg

=102.93 gm

8 0
3 years ago
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