Answer:
7213.7kg/m³
Explanation:
Given parameters:
Volume of the metal chunk = 0.131m³
Mass of the metal chunk = 945kg
Unknown:
Density of the metal chunk = ?
Solution :
To solve this problem, density is the mass per unit volume. It is mathematically expressed as;
Density = 
So;
Density = 
= 7213.7kg/m³
Explanation:
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Hope it helps.
Answer: The correct answer is (a).
Explanation:
The potential energy is due to the position of the object.
The kinetic energy is due to the motion of the object.
In the case of a basketball sitting on a shelf, the basketball posses the potential energy due to some height.
In the case of a dog running across a field, a dog has kinetic energy due to its motion.
In a case of a bowling ball rolling down a lane, there is kinetic energy due to the motion of the bowling ball.
In the case of a teenager riding their bike, there is kinetic energy due to the motion of the bike.
Therefore, the correct answer is (a).
Answer:
magnitude=34.45 m
direction=
Explanation:
Assuming the initial point P1 of this vector is at the origin:
P1=(X1,Y1)=(0,0)
And knowing the other point is P2=(X2,Y2)=(19.5,28.4)
We can find the magnitude and direction of this vector, taking into account a vector has a initial and a final point, with an x-component and a y-component.
For the magnitude we will use the formula to calculate the distance 
between two points:
(1)
(2)
(3)
(4) This is the magnitude of the vector
For the direction, which is the measure of the angle the vector makes with a horizontal line, we will use the following formula:
(5)
(6)
(7)
Finding 
:
(8)
(9) This is the direction of the vector
Answer:
The net change in the internal energy of the gas in the piston is -343J
Explanation:
Because heat and workdone are the only means of energy transfer between the system and the surrounding, change in internal energy is given by;
∆E = q + w
q = heat transfer
w = workdone
Because heat is lost by the system, the heat transfer is negative
q = -413J
Because work is done on the system, workdone is positive
w = +70J
∆E = -413J + 70J
∆E = -343J
