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3 years ago

What is responsible for the production of x ray emission at the cutoff wavelength?

Physics

1 answer:

Katen [24]3 years ago

3 0

Answer:

correct answer is option 5 (The emission by the incident electron when it loses its energy in a single emission)

Explanation:

The emission by the incident electron when it loses its energy in a single emission then X-rays of minimum wavelength which is also known as X-rays of cut-off wavelength are emitted.

If potential V is applied on coolidge tube then cut-off wavelength of the continuous X-ray spectrum is related to the accelerating potential V by following equation

$\lambda_{cut-off} =\frac{hc}{eV} =\frac{12400}{V}$ Angstrom/V

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Suppose a 49-N sled is resting on packed snow. The coefficient of kinetic friction is 0.11. If a person weighing 585 N sits on t

Andre45 [30]

Answer:

69.74 N

Explanation:

We are given that

Weight of sled=49 N

Coefficient of kinetic friction $,\mu_k=0.11$

Weight of person=585 N

Total weight==mg=49+585=634 N

We know that

Force needed to pull the sled across the snow at constant speed,F=Kinetic friction

$F=\mu_k N$

Where N= Normal=mg

$F=0.11\times 634=69.74 N$

Hence, the force is needed to pull the sled across the snow at constant speed=69.74 N

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3 years ago

What is the length x of the side of the triangle below? (Hint: use the cosine function.)

Firlakuza [10]

A because that is the answer

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3 years ago

In a sound wave, the wavelength is equivalent to the distance from a region of high pressure to the region of mean

Alex

F!!! that is false.

4 0

3 years ago

Indicate the substance that is NOT an element.

Volgvan

Water is Not an element

4 0

3 years ago

1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground

Svetradugi [14.3K]

You have three known variables:

Acceleration - $9.8m/s^2$
Time - $1.85s$
Initial Velocity - $0m/s$

For the first part of your question:

$v = u + at

v = (0)+(9.8)(1.1)

v = 10.78 m/s v=11 m/s (2 significant figures)$

For the second part of your question:

$v=u+at

v=(0)+(9.8)(1.85)
v=18.13 m/s

$

This still needs to be converted to m/h:

$18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour

65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h

= 41 mi/hr (2 significant figures)
$

5 0

4 years ago

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