Let's assume that ground level is the height 0 meters. The change in potential energy is going to be gravitational potential energy, which is given by PE=mgh.
ΔPE=mgh-mgy
=mg(h-y)
=50(28-0)
=1400 J
Answer: 65000 × (0.08 × 200 × 0.004) ÷ (800 × 300) = .0
Explanation: .08 × 200 = 16
65000 × (16 × 0.004) ÷ (800 × 300)
16 × .004 = .064
65000 × (.064) ÷ (800 × 300)
65000 × .064 ÷ (800 × 300)
65000 × .064 = 4160
4160 ÷ (800 × 300)
800 × 300 = 240000
4160 ÷ (240000)
4160 ÷ 240000
4160 ÷ 240000 = .01733333333333333
.01733333333333333
Round .01733333333333333 → .00[[]] (Sig Figs: 1)
Answer:
ISTANCIA DEL LANZAMIENTO – 43 pies (13.11m) desde el plato de home para mujeres 46 pies (14.0m) desde el plato de home para hombres.
Hi there!
We can calculate linear momentum using the following:
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
Calculate:
Now, we can relate force, time, and momentum with the following:
I = Impulse (kgm/s)
F = Force (N)
t = time (s)
Rearrange to solve for force:
The impulse is equal to the change in momentum. Since the car comes to a halt, all of its momentum is lost, so:
Solve:
**Negative force since the positive direction is towards the wall, and the negative direction is away from the wall.