What is responsible for the production of x ray emission at the cutoff wavelength?
1 answer:
Answer:
correct answer is option 5 (The emission by the incident electron when it loses its energy in a single emission)
Explanation:
The emission by the incident electron when it loses its energy in a single emission then X-rays of minimum wavelength which is also known as X-rays of cut-off wavelength are emitted.
If potential V is applied on coolidge tube then cut-off wavelength of the continuous X-ray spectrum is related to the accelerating potential V by following equation
Angstrom/V
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Using geometrical arguments, we can see that the angle of the inclined plane 
is equal to the angle between Fg and the perpendicular force.
But the perpendicular force is the projection of Fg along the perpendicular axis, and Fg=mg, so the correct answer is
<span>C) F=mg cosΘ </span>
But the perpendicular force is the projection of Fg along the perpendicular axis, and Fg=mg, so the correct answer is
<span>C) F=mg cosΘ </span>
Answer:
W = 0
Explanation:
When an electron moves perpendicular to a uniform B-field. If the field is in a vacuum, the magnetic field B is the dominant factor determining the motion. Since the magnetic force F is perpendicular to the direction of travel, an electron follows a curved path in a magnetic field. The electron continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force F is always perpendicular to velocity v, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.
W = F*d*Cos ∅ = F*d*Cos 90° = 0 where d is the displacement.
The pic shown can help to understand the explanation.
