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Ray Of Light [21]
1 year ago
10

Need help answering this question

Chemistry
1 answer:
a_sh-v [17]1 year ago
4 0

Answer:

1st = saturated

Explanation:

Bro first ka answer saturated he

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If a temperature increase from 21.0 ∘c to 35.0 ∘c triples the rate constant for a reaction, what is the value of the activation
Airida [17]

Answer:

59.077 kJ/mol.

Explanation:

  • From Arrhenius law: <em>K = Ae(-Ea/RT)</em>

where, K is the rate constant of the reaction.

A is the Arrhenius factor.

Ea is the activation energy.

R is the general gas constant.

T is the temperature.

  • At different temperatures:

<em>ln(k₂/k₁) = Ea/R [(T₂-T₁)/(T₁T₂)]</em>

k₂ = 3k₁ , Ea = ??? J/mol, R = 8.314 J/mol.K, T₁ = 294.0 K, T₂ = 308.0 K.

ln(3k₁/k₁) = (Ea / 8.314 J/mol.K) [(308.0 K - 294.0 K) / (294.0 K x 308.0 K)]

∴ ln(3) = 1.859 x 10⁻⁵ Ea

∴ Ea = ln(3) / (1.859 x 10⁻⁵) = 59.077 kJ/mol.

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Choose the covalent compounds from the following choices Br2 MgS SO2 KF
Novosadov [1.4K]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent Bond

                

                Between 0.4 and 1.7 then it is Polar Covalent Bond

            

                Greater than 1.7 then it is Ionic

 

For Br₂;

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                                                   ________

                    E.N Difference             0.00          (Non Polar Covalent Bond)


For MgS;

                    E.N of Sulfur               =   2.58

                    E.N of Magnesium      =   1.31

                                                   ________

                    E.N Difference                  1.27          (Ionic Bond)


For SO₂;

                    E.N of Oxygen      =   3.44

                    E.N of Sulfur          =   2.58

                                                   ________

                    E.N Difference             0.86          (Polar Covalent Bond)


For KF;

                    E.N of Fluorine          =   3.98

                    E.N of Potassium      =   0.82

                                                   ________

                    E.N Difference                3.16          (Ionic Bond)

Result: The Bonds in Br₂ and SO₂ are Covalent in Nature.

3 0
3 years ago
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