<h2>true</h2>
I did it on my calculater and the answer came as 13
hope that helps :)
Answer:
D. Open the compass so that the distance from the two points of the compass is wider than half the length of 
.
Step-by-step explanation:
To construct a perpendicular for , we must first take a compass & take the distance of its arms wider than half the length of .
This is done in order to get two intersecting arcs in the top & bottom of so that a perpendicular bisector can be drawn through it.
After two intersecting lines are drawn below & above , draw a line joining these 2 points through their points of intersection. The point where it intersects is the middle-most point of & now a perpendicular bisector of is constructed.
Commenter jdoe said it right: solve for y and leave the rest on the other side.
-x + 3y = 6
3y = 6 + x add x on both sides
3y = x + 6 rearrange to get the x first
y = (x + 6) /3 divide both sides by 3
y = x/3 + 6/3 split the numerator (caution - never split denominators)
y = x/3 + 2 simplify 6/3
Thus the line in slope intercept form of y = mx + b is y = 
The y intercept in the equation is -2. What is your question?
Answer:
a = p * q
b = p * s + q * r
c = r * s
Step-by-step explanation:
In the trinomial ax² + bx + c
a is the coefficient of x²
b is the coefficient of x
c is the numerical term
∵ The trinomial is ax² + bx + c
∵ Its factors are (px + r) and (qx + s)
∴ ax² + bx + c = (px + r)(qx + s)
∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)
∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs
∴ ax² + bx + c = pqx² + (ps + qr)x + rs
→ By comparing the two sides
∵ ax² = pqx² ⇒ divide both sides by x²
∴ a = pq
∵ bx = (ps + qr)x ⇒ Divide both sides by x
∴ b = ps + qr
∴ c = rs
∴ a = p * q
∴ b = p * s + q * r
∴ c = r * s
