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alekssr [168]
3 years ago
8

Provide two examples of a metal oxide and explain what they are used for

Chemistry
1 answer:
vekshin13 years ago
3 0

Magnesium Oxide - Used as an electrical insulator.

Calcium Oxide - Used for water purification.

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Select the correct scientist for each of the following advances in creating the modern periodic table.
sergey [27]

Answer:

Lavoisier; Newlands; Moseley

Explanation:

In 1789, Antoine Lavoisier grouped the elements into gases, nonmetals, metals, and earths.

In 1865, John Newlands developed the Law of Octaves. He stated that "any given element will exhibit analogous behaviour to the eighth element following it in the table."  

In 1914, Henry Moseley found a correlation between the X-ray wavelength of an element and its atomic number. He was then able to restructure the periodic table according to atomic numbers.

3 0
3 years ago
Read 2 more answers
Indicate whether aqueous solutions of each of the following solutes will contain only ions, only molecules, or mostly molecules
Zanzabum

Answer:

Following are the solution to the given points:

Explanation:

In point a, the answer is only ions because of NH_4Cl has a strong electrolyte.

In point b, the answer is the only molecules because of ethanol CH_3CH_2OH, it has a nonelectrolyte.

In point c, the answer is the few ions because of hydrocyanic acid HCN, which has a weak electrolyte.

6 0
3 years ago
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
3 years ago
What volume would be needed to prepare 375 mL of a .45 M CaCl2 using only a solution of 1.0 M CaCl2 and water?
Neporo4naja [7]

Answer:

168.75 ml

Explanation:

M1V1=M2V2

375ml*.45M=1M*V2

8 0
3 years ago
Polar molecules have _____.
Ksju [112]

Answer:

B. Charges ( a slight positive charge on one end, and a slight negative charge on the other).

4 0
2 years ago
Read 2 more answers
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