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mojhsa [17]
3 years ago
6

To prevent a condition called the “bends”, deep sea divers breathe a mixture containing, in mole percent, 10.0% O2, 10.0% N2 , a

nd 80.0% He.. a.Calculate the molar mass of this mixture.. b.What is the ratio of the density of this gas to that of pure Oxygen?
Chemistry
2 answers:
Anna [14]3 years ago
5 0
The molar mass of the mixture is the summation of the molar mass of a compound in a mixture to its respective molar mass. In this case, 0.10*32 g/mol added to 0.10*28 g/mol and 0.80 *4 g/mol is equal to 9.2 g/mol. The density ratio of the gas to pure oxygen is the ratio of the molar mass between the two, hence 9.2/32 is 0.2875. 
zmey [24]3 years ago
3 0
Molar mass = <span>0.1 * <span>M<span>O2 </span></span>+ 0.1 * <span>M<span>N2 </span></span>+ 0.8 * <span>M<span>He
molar mass = </span></span></span><span>9.2 g / mo


</span>

For the second part, use PV=nRT, arranged for density. <span>The density ratio of the gas to pure oxygen is the ratio of the molar mass between the two</span>

ratio = PM / RT

ratio = 9.2 / 32 

ratio = 0.2875

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