Answer:
Explanation:
Expression for capillary rise is as follows
h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.
T = .032 J m⁻²
ρ = .71 g / cm³
= 7100 kg / m³
r = .1 x 10⁻³ m = 10⁻⁴ m
h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )
h = .0092 m
= 9.2 mm .
Mass SrBr2 = 247.42 g/mol x 1.36 mol
<span>= 336 g</span>
I want to say addition. But I have a tendency to be wrong
Answer:
35750.4 Joules
Explanation:
Using the formula as follows;
Q = m × c × ∆T
Where;
Q = amount of heat (joules)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to the provided information,
mass (m) = 320.0 grams
c = 4.2 J/g°C
∆T = (50.8°C - 24.2°C) = 26.6°C
Q = ?
Using; Q = m × c × ∆T
Q = 320 × 4.2 × 26.6
Q = 35750.4 J
N(Na₂SO₄)=3 mol
n(O)=4n(Na₂SO₄)
n(O)=4*3=12 mol
