How do I solve and graph this?
1 answer:
3x -y ⩾ 6
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.
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Answer:
<em>If statement(1) holds true, it is correct that </em><em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em><em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers and
.
To check whether is an integer:
Condition (1):
Every factor of is also a factor of
.
Let us consider an example:
which is an integer.
Actually, in this situation is a factor of
.
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let
which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em><em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em><em> is an integer.</em>
<em></em>