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inn [45]
3 years ago
8

How do I solve and graph this?

Mathematics
1 answer:
lianna [129]3 years ago
3 0
3x -y ⩾ 6

3x - 6 ⩾ y

now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".

if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,

3(4) - 0 ⩾ 6

12 - 0 ⩾ 6

12 ⩾ 6   

is 12 really greater or equals to 6?  well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.

now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.

check the picture below.

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Given: 315/1575. Write the prime fractorization of the numerator and the denominator, then write the fraction in lowest terms.
Ne4ueva [31]
The prime factorization of the numerator, 315, is 5 x 3 x 3 x 7. That of the denominator, 1575 is 5 x 5 x 3 x 3 x 7. To convert the fraction to its lowest form, cancel all the factors that appear to both the numerator and denominator. We will be left with 1/5. 
3 0
3 years ago
Question:there are two 12 empty juice bottles. You drank 8 bottles of juice.i drank the rest. What fraction did I drank?
LenKa [72]
Isn't it impossible to drink from an empty bottle?
8 0
3 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
Isaac Green Elimination (Level 1) Mar 17, 8:18:58 AM Find the solution of the system of equations. 8x + y = -13 8r 2y = 10​
kicyunya [14]

Answer:

y = 23

x = -4.5

Step-by-step explanation:

Given:

Equation

8x + y = -13 ......eq1

8x + 2y = 10​........eq2

Find:

Solution

Computation:

Eq2 - Eq1

y = 23

From eq1

8x + y = -13

8x + 23 = -13

8x = -36

x = -4.5

5 0
3 years ago
A student has a savings account with d dollars in it. The student plans to withdraw w dollars each month for
Amiraneli [1.4K]

Answer:

b = d -wn

Step-by-step explanation:

b = d -wn

Here, n is an independent variable and b is an dependent variable in an linear relation, and d and w are two constant values.

Hope it will find you well.

8 0
3 years ago
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