solution:
write the coordinates of the points A and B
A= (0,0,14)ft
B= (5,-6,0)ft
write the position vector of a with recpect to b
R_{BA}=(0-5)i+(0-(-6))j+(14-0)k
=-5i+6k+14k
calculation of a magnitude of the vector R_{BA}
\left | R_{BA} \right |=\sqrt{(-5)^2+6^2+14^2}
=\sqrt{25+36+196}
=16.031ft
calculation of the unit vector
\frac{-5i+6k+14k}{16.031}
calculation of the force
F_{BA}=R_{BA}U_{BA}
here, F_{BA} is the magnitude of the force.
substitute 350lb for F_{BA} and (\frac{-5i+6k+14k}{16.031}) for U_{BA}.
F_{BA} = 350 x (\frac{-5i+6k+14k}{16.031})
=-109.2i+131j+305.7k lb
You are given the mass of the book with an initial
height of 0.77m. You are also given the final height of the book, 2m above the
floor. The problem requires you to find the work done on the book. It is said
that work is equal to force times distance. And that force is equal to mass
times acceleration due to gravity.
W=Fd
W=mgd=mgh
W=(1.7kg)(9.8m/s^2)(2m-0.77m)
W=20.49J
<span>The work is equal to 20.49J.</span>
Answer:
Energy is an essential part of life because all of human activities require energy.
Nuclear fusion, converts hydrogen atoms into helium
Answer:0.210 ft/min
Explanation:
Given
Length of trough
width of base
height of triangle
From Similar triangles property
volume of water in time t
differentiating
at