The number we need in order to answer the question belongs in the space between the words "is" and "of". You left that blank blank, so there really isn't any question here to answer.
HOWEVER ... the refractive index of a medium can never be less than 1.0 , so we know for sure that <em>choice-a can't be</em> the correct answer.
Velocity, because if an object is in motion with no direction we will consider it as speed, but if it has direction we will consider it as Velocity. Hope it helps
Answer:
Explanation:
BMI= weight/(height × height) ; weight in kilogram and height in metter
= 58kg / (1.61m × 1.61m )
= (58/ 2.5921) kg/
= 22.375 kg/
≈ 22.4 kg/
Answer:
a) m = 10 and b) λ = 3.119 10⁻⁷ m
Explanation:
In the diffraction experiments the maximums appear due to the interference phenomenon modulated by the envelope of the diffraction phenomenon, for which to find the number of lines within the maximum diffraction center we must relate the equations of the two phenomena.
Interference equation d sin θ = m λ
Diffraction equation a sin θ = n λ
Where d is the width between slits (d = 0.2 mm), a is the width of each slit (a = 0.02 mm). θ is the angle, λ the wavelength, m and n are an integer.
Let's find the relationship of these two equations
d sin θ / a sin θ = m Lam / n Lam
The first maximum diffraction (envelope) occurs for n = 1, let's simplify
d / a = m
Let's calculate
m = 0.2 / 0.02
m = 10
This means that 10 interference lines appear within the first maximum diffraction.
b) let's use the interference equation, remember that the angles must be given in radians
θ = 0.17 ° (π rad / 180 °) = 2.97 10⁻³ rad
d sin θ = m λ
λ = d sin θ / m
λ = 0.2 10⁻³ sin (2.97 10⁻³) / 2
λ = 3.119 10⁻⁷ m
Answer:
<em>d. The sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>
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Explanation:
Let us take the momentum of a photon unit as u
we know that the rate of change of momentum is proportional to the force exerted.
For a absorbing surface, the photon is absorbed, therefore the final momentum is zero. From this we can say that
F = (u - 0)/t = u/t
for a unit time, the force is proportional to the momentum of the wave due to its energy density. Therefore,
F = u
For a reflecting surface, the momentum of the wave strikes the sail and changes direction. Since we know that the speed of light does not change, then the force is proportional to
F = (u - (-u))/t = 2u/t
just as the we did above, it becomes
F = 2u.
From this we can see that the force for a reflective sail is twice of that for an absorbing sail, and we know that the pressure is proportional to the force for a given area. From these, we conclude that <em>the sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>
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