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madreJ [45]
3 years ago
12

Which type of matter is gold an element used in making jewelry A.) A heterogeneous mixture B.) A pure substance C.) A crystallin

e compound D.) A homogeneous mixture
Physics
2 answers:
Mnenie [13.5K]3 years ago
7 0

Answer:

A

Explanation:

<em>The gold used in the making of jewelry is usually not pure but a heterogeneous mixture of metals. Pure gold is quite soft and even though it may look better in appearance compared to those made using heterogeneous mixtures, it usually bends easily. Hence, in order to make the jewelry more durable, gold is usually mixed with other metals to form a heterogeneous mixture. </em>

The correct option is A.

DaniilM [7]3 years ago
4 0

Answer:

BBBBBBBBB

Explanation:

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1. Which of the following are examples of natural resources
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4 0
3 years ago
Imagine you have a collection of identical flat-bottomed coffee filters that can be nested (stacked inside of each other) so tha
skad [1K]

Answer:

the terminal velocity of 14 nested coffee filters is 3.2 m/s

Explanation:

Given the data in the question;

we know that;

The terminal velocity is proportional to the square root of weight.

v ∝ √W

v = k√W

the proportionality constant depends upon the surface area and the density of the medium (like air). The coffee filters can be stacked such that the resulting area is roughly unchanged. So, the constant of proportionality k is also unchanged

v/√W = constant

v₂/√W₂ = v₁/√W₁

v₂ = v₁√(W₂ / W₁ )

given that;

v₁ = 0.856 m/s,

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so we substitute

v₂ = 0.856 √(14W₁  / W₁ )

v₂  = 0.856 √( 14( W₁/W₁)

v₂  = 0.856 √( 14(1)

v₂  = 0.856 √( 14 )

v₂  = 0.856 × 3.741657

v₂  = 3.2 m/s

Therefore, the terminal velocity of 14 nested coffee filters is 3.2 m/s

6 0
3 years ago
Set the initial bead height to 3.00 m. Click Play. Notice that the ball makes an entire loop. What is the minimum height require
strojnjashka [21]

Answer:

h> 2R

Explanation:

For this exercise let's use the conservation of energy relations

starting point. Before releasing the ball

       Em₀ = U = m g h

Final point. In the highest part of the loop

       Em_f = K + U = ½ m v² + ½ I w² + m g (2R)

where R is the radius of the curl, we are considering the ball as a point body.

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we substitute

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Energy is conserved

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       h = v² / g + 2R

 

The lowest velocity that the ball can have at the top of the loop is v> 0

      h> 2R

3 0
3 years ago
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