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Lady bird [3.3K]
4 years ago
9

What is the change in electric potential energy in moving an electron from a location 3 × 10-10 m from a proton to a location 7

× 10-10 m from the proton? The result should be in joules, with an appropriate sign.
Physics
1 answer:
joja [24]4 years ago
5 0

Answer:

4.39 x 10^-19 J

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r1 = 3 x 10^-10 m

r2 = 7 x 10^-10 m

The formula for the potential energy is given by

U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)

U1 = - 7.68 x 10^-19 J

U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)

U2 = - 3.29 x 10^-19 J

Change in potential energy is

U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J

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If an object with a mass of 248kg is lifted 76 meters in 18 seconds, how much power is used?
Jlenok [28]

Explanation:

power = 1/2 mass × velocity^2 >>1

velocity = distance / time = 76 /18 = 4.2m

then power = 1/2 × 276 × (4.2)^2 = 138 × 17.64 = 2,434.3 jules.

3 0
3 years ago
From the top of a cliff overlooking a lake, a person throws two stones. The two stones have identical initial speeds of v0 = 13.
Alina [70]

Answer:

X = 15.88 m

Explanation:

Given:

Initial Velocity V₀ = 13.4 m/s

θ = 30.1 °

g = 9.8 m/s²

To Find horizontal distance let "X" we have to time t first.

so from motion 2nd equation at Height h = 0

h = V₀y t + 1/2 (-g) t ²                                (ay = -g)

0 = 13.4 sin 30.1° t - 0.5 x 9.81 x t²           (V₀y = V₀ Sin θ)

⇒  t = 1.37 s

Now For Horizontal distance  X, ax =0m/s²

X = V₀x t + 1/2 (ax) t ²

X = 13.4 m × cos 30.1° x 1.37 s + 0

X = 15.88 m

8 0
4 years ago
Please answer someone!!
Naily [24]

Answer:

10m

Explanation:

3 0
3 years ago
Total energy of an orbiting satellite is negative of its Kinetic or potential energy​
Over [174]
Total energy of an orbiting satellite is negative of Its [Kinetic energy].
5 0
3 years ago
The coefficent of static friction between the floor of a truck and a box resting on it is 0.38. The truck is traveling at 87.9 k
nekit [7.7K]

Answer:

d=79.9m

Explanation:

From the question we are told that:

coefficient of static friction \mu=0.38

Velocity v=87.9=>24.41667m/s

Generally the equation for Conservation of energy is mathematically given by

 \mu*mgd = 0.5 m v^2

 d=\frac{0.5*24.42^2}{0.38*9.8}

 d=79.9m

3 0
3 years ago
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