Question

Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 48.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

Answer 1

Explanation:

Initial speed of the incident water stream, u = 16 m/s

Final speed of the exiting water stream, v = -16 m/s

The mass of water per second that strikes the blade is 48.0 kg/s.

We need to find the magnitude of the average force exerted on the water by the blade. The force acting on an object is given by :

$F=\dfrac{m(v-u)}{t}$

Here, $\dfrac{m}{t}=48\ kg/s$

$F=48\times (-16-16)\ N\\\\F=-1536\ N\\\\|F|=1536\ N$

So, the magnitude of the average force exerted on the water by the blade is 1536 N.