The runner has initial velocity vector
and acceleration vector
so that her velocity at time 
is
She runs directly east when the vertical component of 
is 0:
It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time would be
so that after 10.4 s, her position would be
which is 19.9 m away from her starting position.
Wavelength*frequency=velocity
(331m/s)/(.6m)
Frequency = 551.666 1/s
Explanation:
Minimum of aerobic activity 150 minutes, or a mix of moderates and intensive exercise 75 minutes of vigorous aerobic activity a week. We can extend this practice throughout the week with the instructions. Mild aerobic workouts might include practices like quick strolling or swimming, while activity like running can include strong aerobic activity.
Answer:
696.83 m/s
Explanation:
m = mass of water = 565 g = 0.565 kg
c = specific heat of water = 4186 J/(kg⁰C)
ΔT = Change in temperature = T₂ - T₁ = 80 - 22 = 58 ⁰C
v = speed gained by water
Using conservation of energy
Kinetic energy gained by water = heat required to warm water
(0.5) m v² = m c ΔT
(0.5) v² = c ΔT
(0.5) v² = (4186) (58)
v = 696.83 m/s
