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mrs_skeptik [129]
3 years ago
11

Suppose that an object in free fall were somehow equipped with a speedometer. by how much would its speed readings increase with

each second of fall?
Physics
1 answer:
alina1380 [7]3 years ago
5 0
The speed would increase by however much the acceleration due to gravity is. On earth, I believe that is 32ft/s or 9.8m/s
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In this example we will analyze the forces acting on your body as you move in an elevator. Specifically, we will consider the ca
dexar [7]

Answer:

The reading of the scale during the acceleration is 446.94 N

Explanation:

Given;

the reading of the scale when the elevator is at rest = your weight, w = 600 N

downward acceleration the elevator, a = 2.5 m/s²

The reading of the scale can be found by applying Newton's second law of motion;

the reading of the scale  = net force acting on your body

R = mg + m(-a)

The negative sign indicates downward acceleration

R = m(g - a)

where;

R is the reading of the scale which is your apparent weight

m is the mass of your body

g is acceleration due to gravity, = 9.8 m/s²

m = w/g

m = 600 / 9.8

m = 61.225 kg

The reading of the scale is now calculated as;

R = m(g-a)

R = 61.225(9.8 - 2.5)

R = 446.94 N

Therefore, the reading of the scale during the acceleration is 446.94 N

4 0
3 years ago
Plz Help me This is all my homework The one is orange is the ones i need help in
IrinaVladis [17]

Convection is the transfer of heat through a fluid

Conduction is the heat or electric current from one substance to another

Radiation is energy that radiated or transmitted

Ex: Convection- A pot of water is being boiled- the heat is being transferred to to the water

Ex2: Conduction- I have a plate filled with hot food- the heat from the food is being transferred to the plate, making the plate hot as well.

Ex3: Radiation- There is a dog by the fire place, the dog is being warmed- the heat from the fire is being transferred over to the dog

Hope this will help you with your homework :)

8 0
3 years ago
Read 2 more answers
A 60 kilogram astronaut weighs 96 newtons on the surface of the moon. calculate the acceleration due to gravity on the moon.
34kurt
Given: Mass m = 60 Kg

           Weight  W = 96 N

Required: Acceleration due to gravity, g = ?

Formula:  W = mg

                g = W/g

                g = 96 Kg.m/s²/60 Kg   (note: this is the derive unit for Newton "N")

                g = 1.6 m/s²

6 0
3 years ago
Read 2 more answers
The north pole of a bar magnet is rapidly introduced into a solenoid at one end (say A). Which of the following statements corre
krek1111 [17]

Answer:

The correct option is;

(b) The end A of the solenoid behaves like a north pole

Explanation:

According to Lenz's law we have that the induced emf direction in the solenoid due to the rapid introduction of the bar magnet will be such that the electric current induced will have a resultant magnet field that will  oppose to the movement of the north pole of the bar magnet that resulted in the magnetic field

Therefore, the opposing magnetic pole to the north pole of a magnet is a north pole and the solenoid end A will act like the north pole.

5 0
3 years ago
A tension force of 175 N inclined at 20.0° above the horizontal is used to pull a 40.0 - kg packing crate a distance of 6.00 m o
Murljashka [212]

Answer:

(a) Work done by the tension force is 987 J

(b) Coefficient of kinetic friction between the crate and surface is 0.495

Explanation:

(a)

Work done by any force F in moving an object by a distance d making an angle \Theta with the direction of force  is given by

W=Fd\cos (\Theta )

W=175 \times 6 \times  \cos (20 )J=987J

Thus work done by the tension force is 987 J

(b)

Normal force on the crate is given by

N= mg-F\sin \Theta  =(40\times 9.8-175\times \sin 20)Newton

=>N=332 Newtons

Since crate is moving with constant speed . Therefore using Newtons second law .

Fcos(\Theta ) -\mu_k N=0

Where \mu_k=coefficient of kinetic friction

\therefore \mu_k=\frac{F\cos (\Theta )}{N}

=>\mu_k=\frac{175\times \cos 20}{332}

=>\mu _k= 0.495

Thus coefficient of kinetic friction between the crate and surface is 0.495

4 0
3 years ago
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