Answer:
The work done on the canister is 15.34 J.
Explanation:
Given;
mass of canister, m = 1.9 kg
magnitude of force acting on x-y plane, F = 3.9 N
initial velocity of canister in positive x direction,
= 3.9 m/s
final velocity of the canister in positive y direction, 
The change in the kinetic energy of the canister is equal to net work done on the canister by 3.9 N.
ΔK.E = 
ΔK.E 
The initial kinetic energy of the canister;

The final kinetic energy of the canister;

ΔK.E = 29.79 J - 14.45 J
ΔK.E =
= 15.34 J
Therefore, the work done on the canister is 15.34 J.
Explanation:
I don't have time for you
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