Answer:
q = 1.815 \times 10^{-8} C
Charge on one plate is positive in nature and on the other plate it is negative in nature.
Explanation:
E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm
According to the Gauss's theorem in electrostatics
The electric field between the two plates




Charge, q = surface charge density x area

q = 1.815 \times 10^{-8} C
Your position at time
, relative to the stop line:

The Porsche's position:

a. You pass the Porsche immediately after the time it takes for
:

at which point you both will have traveled 7.8 m from the stop line.
b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about
, at which point you both will have traveled 29 m.
c. At time
, the Porsche is moving at velocity

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.
Answer:
3.72 m/s²
Explanation:
Horizontal component of the force applied = Fcosθ = 86 cos 30 = 74.478 N
Force = mass × acceleration = 74.478 N
ma = 74.478 N
a = 74.478 / 20 since friction can be neglected = 3.72 m/s²
Its C. a decrease in the radius and an increase in the tangential speed ,I'm 100% sure