A water rocket can reach a speed of 75 m/s in 0.050 seconds from launch. What is its average acceleration?

Physics

2 answers:

yanalaym [24]3 years ago

6 0

A=v/t
So therefore 75/0.050= acceleration
So the answer is a= 1500 metres per second per second

Andru [333]3 years ago

6 0

Answer:

$a = 1500 m/s^2$

Explanation:

Initial speed of the rocket is ZERO as it starts from rest

$v_i = 0$

final speed of the rocket is 75 m/s

$v_f = 75 m/s$

so we will say that average acceleration is defined as rate of change in velocity

so it is given as

$a = \frac{v_f - v_i}{\Delta t}$

$a = \frac{75 - 0}{0.05}$

$a = 1500 m/s^2$

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