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Anastaziya [24]

3 years ago

9

During free fusion, the eyes _______ in order to view a stereogram without a stereoscope. A. use the pictorial depth cue B. are

half closed C. use the motion parallax D. converge or diverge E. glaze over

1 answer:

Andru [333]3 years ago

7 0

Answer:

D

Explanation:

During free fusion, the eyes converge or diverge in order to view a stereogram without a stereoscope.

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Fill in the blanks. When the northern hemisphere experiences _________, the southern hemisphere experiences __________.

schepotkina [342]

I choose the letter B

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3 years ago

Zero field spot for opposite unequal charges

xz_007 [3.2K]

Answer:

The zero field location has to be on the line running between the two point charges because that's the only place where the field vectors could point in exactly opposite directions. It can't be between the two opposite charges because there the field vectors from both charges point toward the negative charge.

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3 years ago

A wrench is accidentally dropped at the top of an elevator shaft in a tall building. (a) How many meters does the wrench fall in

RUDIKE [14]

Answer:

11.25m

Explanation:

$s = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times 1.5 + \frac{1}{2} \times 10 \times {1.5}^{2} \\ = 5 \times 2.25 \\ = 11.25$

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3 years ago

1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa

WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

$W= mg$

$m = \dfrac{W}{g}$

Put the value into the formula

$m=\dfrac{81.34}{9.8}$

$m=8.3\ kg$

The mass per unit length of the wire

$m_{l}=\dfrac{m}{l}$

Put the value into the formula

$m_{l}=\dfrac{8.3}{10000}$

$m_{l}=8.3\times10^{-4}\ kg/m$

We need to calculate the frequency in the wire

Using formula of frequency

$f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}$

Put the value into the formula

$f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}$

$f_{w}=189.62\ Hz$

We need to calculate the beat frequency

Using formula of beat frequency

$f_{b}=f_{in}-f_{w}$

Put the value into the formula

$f_{b}=196-189.622$

$f_{b}=6.378\ Hz$

Hence, The beat frequency is 6.378 Hz.

5 0

3 years ago

Look at the diagram showing resistance and flow of electrons. A top box labeled X contains 2 circles with plus signs and 2 circl

Usimov [2.4K]

Answer:

The answer is D. The electrons will flow from an area of high potential energy to an area of low potential energy.

X== low potential energy

Y = high potential energy

z = flow of electrons

Explanation:

5 0

4 years ago

Read 2 more answers