The period T of a pendulum is given by:
![T=2 \pi \sqrt{ \frac{L}{g} }](https://tex.z-dn.net/?f=T%3D2%20%5Cpi%20%20%5Csqrt%7B%20%5Cfrac%7BL%7D%7Bg%7D%20%7D%20)
where L is the length of the pendulum while
![g=9.81 m/s^2](https://tex.z-dn.net/?f=g%3D9.81%20m%2Fs%5E2)
is the gravitational acceleration.
In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is
![T=0.200 s](https://tex.z-dn.net/?f=T%3D0.200%20s)
. Using this data, we can solve the previous formula to find L:
Answer:
The maximum value of the magnetic field in the given wave is 6.67 nT.
Explanation:
Given;
maximum value of the electric field, E₀ = 2.0 V/m
The maximum value of the magnetic field in the given wave is calculated as;
![B_o = \frac{E_o}{c}](https://tex.z-dn.net/?f=B_o%20%3D%20%5Cfrac%7BE_o%7D%7Bc%7D)
where;
c is the speed of light = 3 x 10⁸ m/s
![B_o = \frac{E_o}{c} \\\\B_o = \frac{2}{3 \ \times \ 10^8} \\\\B_o = 6.67 \ \times \ 10^{-9} \ T\\\\B_o = 6.67 \ nT](https://tex.z-dn.net/?f=B_o%20%3D%20%5Cfrac%7BE_o%7D%7Bc%7D%20%5C%5C%5C%5CB_o%20%3D%20%5Cfrac%7B2%7D%7B3%20%5C%20%5Ctimes%20%5C%2010%5E8%7D%20%5C%5C%5C%5CB_o%20%3D%206.67%20%5C%20%5Ctimes%20%5C%2010%5E%7B-9%7D%20%5C%20T%5C%5C%5C%5CB_o%20%3D%206.67%20%5C%20nT)
Therefore, the maximum value of the magnetic field in the given wave is 6.67 nT.
Answer:
326149.2 KJ
Explanation:
The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:
Q = m*cv*ΔT
Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.
A 65000 L swimming pool will have a mass of:
65000L *
= 65000 kg
The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.
We replace the data and get:
Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ
D. The type of criminal activity
Answer:
Cause, The thickness of the windshield formed between the glass and the lens is zero.