Answer:
c. dioptre that's the answer.
Whatcha need help with ????????
Answer:
Explanation:
Stefan's formula for emission of radiation is
E = e σ A ( T⁴ - T₀⁴ )
E is energy radiated , e is emissivity , σ is stefan's constant , T is temperature of object and T₀ is temperature of surrounding. A is area of surface .
E = .35 x 5.67 x 10⁻⁸ ( 298⁴ - 268⁴ ) x 4π x .25²
= 1.9845 x 10⁻⁸ ( 78.86 - 51.58 ) x 10⁸ x .0625
= 3.38 J /s
Answer:



Explanation:
From the question we are told that
Mass of pitcher 
Force on pitcher 
Distance traveled 
Coefficient of friction 
a)Generally frictional force is mathematically given by



Generally work done on the pitcher is mathematically given as




b)Generally K.E can be given mathematically as

Therefore

c)Generally the equation for kinetic energy is mathematically represented by


Velocity as subject



This is a statement but yes a star forms inside nebulae which are gigantic clouds of gas. stars form inside as the gases own gravity pulls it together after which it becomes large enough to perform fusion and become a star.