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Vera_Pavlovna [14]
2 years ago
14

Unpolarized light of intensity 800 W/m2 is incident on two ideal polarizing sheets that are placed with their transmission axes

perpendicular to each other. An additional polarizing sheet is then placed between the two, with its transmission axis oriented at 30∘ to that of the first. What is the intensity of the light passing through the stack of polarizing sheets? (Express your answer to two significant figures.)
Physics
1 answer:
Lady_Fox [76]2 years ago
3 0

Answer:

75 W/m²

Explanation:

I_0 = Unpolarized light intensity = 800 W/m²

\theta = Angle between filters = 30°

Intensity of light after passing through first polarizer

I=\frac{I_0}{2}\\\Rightarrow I=\frac{800}{2}\\\Rightarrow I=400\ W/m^2

Intensity of light after passing through second polarizer

I_1=Icos^2\theta\\\Rightarrow I_1=400\times cos^2(30)\\\Rightarrow I_1=300\ W/m^2

Intensity of light after passing through third polarizer

I_2=I_1cos^2\theta\\\Rightarrow I_2=300\times cos^2(90-30)\\\Rightarrow I_1=75\ W/m^2

The intensity of the light passing through the stack of polarizing sheets is 75 W/m²

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2.1) (i) W = mg downwards
(ii) N = R = Normal Reaction from the ground upwards
(iii) Fe = Force of engine towards the right
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a \:  =  \:  \frac{dv}{dt}  \:  =  \:  \frac{25 \:  \frac{m}{s} }{50 \: s} \:  =  \: 0.5 \:  \frac{m}{ {s}^{2} }
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2.2.3)
2ax \:  =  \:  {v}^{2}  \:  -  \:  {u}^{2}
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2.4.2)
x = -625/(2×(-0.5)) = 625 m.
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