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![U4\leq \sqrt{x} \sqrt[n]{x} 64](https://tex.z-dn.net/?f=U4%5Cleq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%2064)
Step-by-step explanation:
73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±
Answer:

Step-by-step explanation:

The descryption gives you the above <em>Slope-Intercept Equation</em>. Parallel equations have SIMILAR <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], therefore
remains as is, and perfourming
will give you that answer.
I am joyous to assist you at any time.
The slope of the parallel line is 3/4
<h3>How to determine the slope?</h3>
The equation is given as:
3x - 4y = 8
Rewrite as:
4y = 3x - 8
Divide through by 4
y = 3x/4 - 2
A linear equation is represented as:
y = mx + b
Where m represents the slope
By comparison:
m = 3/4
Parallel lines have equal slope
Hence, the slope of the parallel line is 3/4
Read more about slope at:
brainly.com/question/3493733
#SPJ1
The answers to your question would be A. Housing B. medical expenses C. Groceries
We have that
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure