Answer:
1632 Hz
Explanation:
We'll begin by calculating the frequency of each wave. This can be obtained as follow:
1st wave:
Velocity (v) = 340 m/s.
Wavelength 1 (λ₁) = 5 m
Frequency 1 (f₁) =?
v = λ₁f₁
340 = 5 × f₁
Divide both side by 5
f₁ = 340 / 5
f₁ = 68 Hz
2nd wave:
Velocity (v) = 340 m/s.
Wavelength 2 (λ₂) = 0.2 m
Frequency 2 (f₂) =?
v = λ₂f₂
340 = 0.2 × f₂
Divide both side by 0.2
f₂ = 340 / 0.2
f₂ = 1700 Hz
Finally, we shall determine the difference in the frequency of both waves.
This can be obtained as follow:
Frequency 1 (f₁) = 68 Hz
Frequency 2 (f₂) = 1700 Hz
Difference =?
Difference = f₂ – f₁
Difference = 1700 – 68
Difference = 1632 Hz
An oxidation-reduction (redox<span>) </span>reaction<span> is a type of chemical </span>reaction<span> that involves a transfer of electrons between two species. An oxidation-reduction </span>reaction<span> is any chemical </span>reaction<span> in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.</span>
Answer:
![K=K_1*K_2\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}](https://tex.z-dn.net/?f=K%3DK_1%2AK_2%5C%5C%5C%5CK%3D%5Cfrac%7B%5BH_2%5D%5E3%5BCO_2%5D%5BH_2%5D%7D%7B%5BCH_4%5D%5BH_2O%5D%5BH_2O%5D%7D)
Explanation:
Hello there!
In this case, for the given chemical reaction, it turns out firstly necessary to write the equilibrium expression for both reactions 1 and 2:
![K_1=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \\\\K_2=\frac{[CO_2][H_2]}{[CO][H_2O]}](https://tex.z-dn.net/?f=K_1%3D%5Cfrac%7B%5BCO%5D%5BH_2%5D%5E3%7D%7B%5BCH_4%5D%5BH_2O%5D%7D%20%5C%5C%5C%5CK_2%3D%5Cfrac%7B%5BCO_2%5D%5BH_2%5D%7D%7B%5BCO%5D%5BH_2O%5D%7D)
Now, when we combine them to get the overall expression, we infer these two are multiplied to get:
![K=K_1*K_2\\\\K=\frac{[CO][H_2]^3}{[CH_4][H_2O]} *\frac{[CO_2][H_2]}{[CO][H_2O]}\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}](https://tex.z-dn.net/?f=K%3DK_1%2AK_2%5C%5C%5C%5CK%3D%5Cfrac%7B%5BCO%5D%5BH_2%5D%5E3%7D%7B%5BCH_4%5D%5BH_2O%5D%7D%20%2A%5Cfrac%7B%5BCO_2%5D%5BH_2%5D%7D%7B%5BCO%5D%5BH_2O%5D%7D%5C%5C%5C%5CK%3D%5Cfrac%7B%5BH_2%5D%5E3%5BCO_2%5D%5BH_2%5D%7D%7B%5BCH_4%5D%5BH_2O%5D%5BH_2O%5D%7D)
Regards!
Choice 2 possibly, not positive
54g ag *(108mol ag/1 g ag) =5832mol ag
