Answer:
The forces acting on the book are balanced by each other.
Answer:
1.0 ° C
Explanation:
The molar mass for Sodium Nitrate NaNO₃ = (23+14+(16×3)) = 85
Number of moles of NaNO₃ = mass of NaNO₃ /molar mass of NaNO₃
⇒ 17/85 = 1.38 moles
Since 1 mole of NaNO₃ dissolved in 1 cubic decimeter of water, 40 kJ of heat energy is absorbed.
when 1.38 mole of NaNO₃ dissolved in 1 cubic decimeter of water, x kJ of heat energy is absorbed..
Then; x kJ of 1.38 mole of NaNo₃ = 1.38 × 40 kJ =55.2 kJ of heat absorbed.
Using the relation : Q = mcΔT to determine the temperature drop ; we get:
55.2 = 17 × 4 (ΔT)
55.2 = 68 ΔT
ΔT= 0.8 ° C
ΔT ≅ 1.0 ° C
Therefore, the drop in temperature when 17.0g of sodium nitrate is dissolved in 1 cubic decimeter of water is 1.0 ° C
5. Eubacteria
6. Plantae
7. Animalia
8. Protist (technically not a kingdom)
9. Archaebacteria
10. Fungi
Answer is: c) CAM.
CAM (crassulacean acid metabolism) is a carbon fixation pathway.
In plants with CAM carbon fixation, carbon dioxide is stored as the malic acid malate in vacuoles at night.
During the daytime, the malic acid is transported to chloroplasts where it is converted back to carbon dioxide, which is then used during photosynthesis.
Malic acid is an organic dicarboxylic acid with the molecular formula C₄H₆O₅.
Answer:
1.18 × 10²⁴ particles Mg
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
47.7 g Mg
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Mg - 24.31 g/mol
<u>Step 3: Convert</u>
<u />
= 1.18161 × 10²⁴ particles Mg
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg
