OMG THERE'S SPIDER BEHIND YOU!!! jk XD lets get back to the question.....
example of omnivores would be us humans but since you said ANIMALS then :
BEARS - bears are omnivores they feed on meat like fish and plants like grass or dandelion.
RACCOONS - their omnivores too they feed on meat like rats (ew), fish, frogs..etc they also eat plants like any kind fruit, grains, nuts ( i dont think all kind tho).
so yup those are two examples :D
Answer:
number of molecules =9.03×10^23
Explanation:
use the equation
n=number of molecules /Av.constant
make number of Molecules become the subject of the formula by multplying Av.constant on both sides of the equation,
number of molecules=n×Av. constant ,where Av.constant is 6.02×10^23
number of molecules=1.5mol×6.02×10^23
=9.03×10^23
7.66g of ethyl butyrate is produced.
The reaction is
CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃
- The molar mass of butanoic acid is 88.11g/mol
- We have 7.45g of butanoic acid
- The moles of butanoic acid we have is 7.45/88.11 = 0.0845 mol
- If the yield is 100%, 1 mole of butanoic acid gives 1 mole of ethyl butyrate
- But the reaction yield is 78%
- 1 mole of butanoic acid gives 0.78 mole of ethyl butyrate
From 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.
The molar mass of ethyl butyrate is 116.16g/mol
So 0.66 x 116.16 = 7.66g
7.66g of ethyl butyrate is produced.
Learn more about esterification here:
brainly.com/question/14028062
#SPJ10
A. To determine how to break down minerals
The first to do is to isolate the constant, k, to one side. The rate expression would then be:
k = rate/ <span>[A][B]^2
This constant, k, will be the same for the given reaction at a certain temperature. Then, we can relate a second rate to this reaction.
</span>rate1/ [A1][B1]^2 = rate2/ [A2][B2]^2
First question:
0.0810 / [A1][B1]^2 = rate2/ <span>[A2/2][3B2]^2
rate2 = (</span>0.0810 [A2/2][3B2]^2 )/ [A1][B1]^2
rate2 = 0.3645 M/s
Second Equation:
0.0810 / [A1][B1]^2 = rate2/ <span>[A2/2][3B2]^2
rate2 = (</span>0.0810 [3A2][B2/2]^2 )/ [A1][B1]^2
<span>rate2 = 0.0608 M/s</span>
