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3 years ago

Net ionic equation of hydrated oxalic acid and sodium hydroxide

Chemistry

1 answer:

blondinia [14]3 years ago

6 0

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Calculate the mass in grams of each sample.

OlgaM077 [116]

Answer: The answer is A. - 4.88x10^20 H2O2 molecules

Explanation: I hope this helps!

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3 years ago

Which of the following affects the speed of a seismic wave?

scoray [572]

Explanation:

The speed of seismic waves is affected by the density of the underlying rock.

Seismic waves are elastic waves that transmits elastic energy from one point to the other.

These waves generally produced during an earthquake.

The higher the density of rock bodies, the faster the wave travels.
Rocks that are well packed with little to no void have a higher seismic velocity.
Where density of rock is low, the speed is also low

3 0

3 years ago

Write the molecular formula of potassium chloride

Naddik [55]

Answer:

KCl is the answers for the question

Explanation:

please give me brainlest

4 0

2 years ago

Read 2 more answers

Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many

Flauer [41]

Answer : The amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

Explanation : Given,

Density of air = $1.2kg/m^3=1.2g/L$ $(1kg/m^3=1g/L)$

First we have to calculate the mass of air.

$\text{Mass of air}=\text{Density of air}\times \text{Volume of air}$

$\text{Mass of air}=1.2g/L\times 6.0L$

$\text{Mass of air}=7.2g$

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = $\frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $5.4\times 10^{-6}g$

Thus, the amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

8 0

3 years ago

titration 25.0 ml of 3.4 x 10^ -3 M of Ba(OH) Neutralize 16.6 mL of HCL solution. What is the molarity of HCL solution?

marusya05 [52]

What we are give: Concentration of base (CB) = 3.4 × $10^{-3}$
Then convert all volume in ml to L.
Volume of base (VB) 25.0ml = 0.025L
Volume of acid (VA) 16.6ml = 0.0166L
Now that we have everything we use the formula CAVA=CBVB.
Make 'CA' the subject then solve.
CA= $\frac{CBVB}{VA}$

8 0

3 years ago