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zavuch27 [327]
2 years ago
14

Why can't air exist in space, but gas can????

Chemistry
1 answer:
MakcuM [25]2 years ago
8 0

Answer:

Earth's gravity is strong enough to hold onto its atmosphere and keep it from drifting into space.

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Solid at room temperature. They are used in making computers and electronic devices. Have properties of both metals and nonmetal
larisa86 [58]

Answers:  metaloids

Explanation:

5 0
2 years ago
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When hno2 dissociates in water, which atom is dontaing electrons, allowing water to act as a lewis base?
miss Akunina [59]

Answer to this is O-atom.

Explanation: The Bronsted acid-base theory is the backbone of chemistry. This theory focuses mainly on acids and bases acting as proton donors or proton acceptors.

A^+ + B^- \rightarrow A-B

where A^+ is the Lewis Acid and B^- is the Lewis Base and A-B is the Covalent Bond.

Reaction of dissociation of HNO2 in H_2O is given as:

HNO_2 + H_2O \rightarrow H_3O^+ + NO_2^-

In this reaction O-atom has lone pair in water and therefore it accepts the proton from HNO_2 forming a Lewis Base.

6 0
3 years ago
Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -> 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0
2 years ago
What is the density of an object having a mass of 5.0 g and a volume of 45.0 cm3?
shutvik [7]
D = m / V

d = 5.0 / 45.0

d = 0.111 g/cm³
7 0
3 years ago
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Natural atom of the same element may have the same _________?
Minchanka [31]

Answer:B

Explanation:

4 0
3 years ago
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