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Tom [10]
3 years ago
5

One source of aluminum metal is alumina, Al2O3. a. Determine the percentage composition of Al in alumina. b. How many pounds of

aluminum can be extracted from 2.0 tons of alumina.?
Chemistry
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

sorry i cant give the answer but you can gi end check in answer sheet of this becoz i had same question in exam in chemistry so i revised then i checked the answer if you want to check answer go to www.coachscotchemistry.com there you xan find the answer

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Using what you have learned about the three forms of writing chemical equations, classify each of the presented equations as eit
suter [353]

Explanation:

Molecular equation: Chemical equation in which molecular formula of reactants and products are written

Complete ionic equation:Chemical equation in which ionic from if reactants reactants and products are written along with spectator ions (ions present on both sides of equation).

Net ionic equation :Chemical equation in which only ions of those reactant are written which giving product without  spectator ions (ions present on both sides of equation).

(a) Ca^{2+}(aq) + SO_4^{2-}(aq)\rightarrow CaSO_4(s)

net ionic equation.

(b) CuSO_4(aq) + 2KOH(aq)\rightarrow Cu(OH))_2(s) + K_2SO_4(aq)

Molecular equation

(c)Ba^{2+} (aq) + SO_4^{2-}(aq)\rightarrow BaSO_4(s)

Net ionic equation.

(d) Ag^+(aq) + NO_{3}^-(aq) + I^-(aq)\rightarrow AgI(s) + NO_{3}^-(aq)

Complete ionic equation

3 0
3 years ago
The relation between stability and solubility​
Tema [17]

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7 0
3 years ago
Which statement is true about compounds? They do not form living things. They do not form nonliving things. They are formed when
oksano4ka [1.4K]

Answer:

The true statement is:

They are formed when atoms of different elements combine.

Explanation:

Compounds are formed when atoms of different elements combine.

Atoms of different elements combine with each other to attain stable electronic configuration.

The atoms can combine with each other in two different ways:

1) By sharing the electrons

2) By exchanging electrons

When they share electrons with each other, they form a covalent bond.

When they exchange electrons, they form an ionic bond.

3 0
3 years ago
A) How many grams of water are produced when 2.50 g of aluminum
egoroff_w [7]
The correct answer is 13 I just did it bro
5 0
2 years ago
g Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produc
Gala2k [10]

\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}

\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}

\text{and in the liquid form it is easily transported. An industrial chemist studying this}

\text{reaction fills a} \ \mathbf{100 \  L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \  \text{of oxygen gas, }

\text{to be} \  \mathbf{2.6\  mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}

\text{ammonia at the final temperature of the mixture. Round your answer to  2 significant digits.}

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

From the above reaction; the ICE table can be represented as:

                    \mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

I (mol/L)     0.086            0.28                 0              0

C                   -4x                -3x               +2x           +6x

E                 0.086 - 4x     0.28 - 3x      +2x             +6x

At equilibrium;

The water vapor = \dfrac{2.6 \ mol}{100 \ L} = 6x

x = \dfrac{2.6}{100} \times \dfrac{1}{6}

x = 0.00433

\text{equilibrium constant}  ({k_c}) =  \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }

\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\

Replacing the value of x, we have:

K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}

K_c = \mathbf{5.5 \times 10^{-8} \ to  \ 2 \ significant \ figures}

5 0
3 years ago
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