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3 years ago

Two metal spheres are suspended from strings. The

Physics

1 answer:

IRINA_888 [86]3 years ago

6 0

Answer:

The answer to your question is the letter B. A repulsive force of 8.0 x 10³N

Explanation:

Data

Charge 1 = -2.0 x 10² C

Charge 2 = -4.0 x 10⁻⁸ C

K (Coulomb constant) = 9 x 10⁹ Nm²/C²

distance = 3 m

Formula

F = K (q₁ x q₂) / r²

Substitution

F = 9 x 10⁹ (-2.0 x 10²)(-4.0 x 10⁻⁸) / 3²

Simplification

F = 9 x 10⁹ (0.000008) / 9

F = 72000 / 9

Result

F = 8000 C = 8 x 10³ N

Conclusion

As both spheres are negative the force is negative with magnitude 8x 10³N

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<h3>What is volume?:</h3>

This is the product of the height of a solid object and its crossectional area.

The Volume of the rod is can be calculated using the formula below.

Note: A rod has the shape of a cylinder.

Formula:

V = πr²h............... Equation 1

Where:

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Substitute these values into equation 1

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This is the ratio of the charge on an object to the length of the object.

The linear charge density of the rod can be calculated using the formula below.

D = Q/h.................... Equation 2

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